Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 04 May 2015, 09:43

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# DS - x and y positive integers

Author Message
TAGS:
Senior Manager
Joined: 01 Feb 2005
Posts: 274
Followers: 1

Kudos [?]: 39 [0], given: 1

DS - x and y positive integers [#permalink]  11 Apr 2007, 02:03
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
What is the answer to this question? When the main stem of the question says, positive integers the exlanation for statement 1 used negative numbers to prove its case that statement 1 was not sufficient.

This confused me a little... Anyone who can clear my misconception?
Attachments

untitled.GIF [ 15.51 KiB | Viewed 441 times ]

SVP
Joined: 01 May 2006
Posts: 1805
Followers: 8

Kudos [?]: 99 [0], given: 0

It's (A)

With y = 2*x, we have

4^x * (1/3)^y
= 2^(2*x) * (1/3)^(2*x)
= (2/3)^(2*x) < 1 as x > 0

It's stated that x & y are both positive integers... Your answer was correct
Senior Manager
Joined: 01 Feb 2005
Posts: 274
Followers: 1

Kudos [?]: 39 [0], given: 1

Phew!! Thanks Fig!! Appreciate it!!
SVP
Joined: 01 May 2006
Posts: 1805
Followers: 8

Kudos [?]: 99 [0], given: 0

axl_oz wrote:
Phew!! Thanks Fig!! Appreciate it!!

U are welcome :D
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5078
Location: Singapore
Followers: 22

Kudos [?]: 184 [0], given: 0

4^x(1/3)^y can be written as (4^x/3^y)

St1:
y = 2x, so we have (4^x/3^y) = (4^x/3^2x) = (4^x/9^x) = (4/9)^x. This is always less than 1. Sufficient.

St2:
y = 4, so we have (4^x/81). We don't know x, so we can't tell if it's smaller or greater than 1. Insufficient.

Ans A
Similar topics Replies Last post
Similar
Topics:
6 If x and y are positive integers, is 4 14 May 2013, 10:21
6 If x and y are positive integers and 7 21 Feb 2012, 13:45
If x and y are positive integers and x is a multiple of y, 3 14 Feb 2007, 12:06
If x and y are positive integers and x is a multiple of y, 6 06 May 2006, 00:07
x and y are positive integers. If x is divided by y, then 3 11 Nov 2005, 07:59
Display posts from previous: Sort by