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# DS - X > Y^2?

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Senior Manager
Joined: 12 Mar 2007
Posts: 275
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Kudos [?]: 39 [0], given: 2

DS - X > Y^2? [#permalink]  04 Aug 2007, 11:13
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Question Stats:

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Is X > Y^2?

1) X > Y+5
2) X^2 - Y^2 = 0

Please explain. Thanks!
Current Student
Joined: 28 Dec 2004
Posts: 3391
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 13

Kudos [?]: 181 [0], given: 2

[#permalink]  04 Aug 2007, 11:31
looks E to me..cant tell if X or Y are positive or negative....
VP
Joined: 10 Jun 2007
Posts: 1465
Followers: 6

Kudos [?]: 133 [0], given: 0

Re: DS - X > Y^2? [#permalink]  04 Aug 2007, 14:29
leeye84 wrote:
Is X > Y^2?

1) X > Y+5
2) X^2 - Y^2 = 0

Please explain. Thanks!

Got C, hope it's right. I spend way more than 2 mins. what' OA?

1) x > y+5
Try x=7, y=1: 7>1 yes!
Try x=1, y=-5: 1>25 No!
INSUFFICIENT.

2) x^2 - y^2 = 0
This is same as |x| = |y|
This means that the sign doesn't matter.
In other word, (+/-)x = (+/-)y
Try x=1, x=-1 => (+/-)1 will not be greater than 1
Try x=0, 0 will not be greater than 0.
Try large number, say x=10
(+/-)10 will not ever be greater than 100
*However, if you plug in 0<x<1, then x>y^2
This means that only 0<x<1 works but not others.
INSUFFICIENT.

Together, we know that x-y > 5. This means that the difference between them is more than 5. From |x|=|y|, it tell us that x and y will always have different sign and their value is at least 2.5
This is actually sufficient to answer the question since x won't be between 0 and 1.

*I edited this post.*
Director
Joined: 03 May 2007
Posts: 894
Schools: University of Chicago, Wharton School
Followers: 6

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Re: DS - X > Y^2? [#permalink]  04 Aug 2007, 19:57
leeye84 wrote:
Is X > Y^2?

1) X > Y+5
2) X^2 - Y^2 = 0

Please explain. Thanks!

C. x is positive and y is negative.

x = lyl

suppose y = - 3, x = 3, which is > y + 5.
suppose y = - 4, x = 4, which is > y + 5.

y must be less than 2.5. or y cannot be 2.5 or grater than -2.5.
Manager
Joined: 08 Oct 2006
Posts: 215
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Kudos [?]: 5 [0], given: 0

[#permalink]  05 Aug 2007, 03:08
I go with C and answer is No.
1. x>y+5. Insufficient

2. lxl=lyl.
Insufficient as both can be 0 or any other integer.

C. x has to be postive and Y has to be -ve. and the x> 2.5

thus x will always be less than y*2.
[#permalink] 05 Aug 2007, 03:08
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# DS - X > Y^2?

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