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During 2005, a company produced an average of 2,000 products

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During 2005, a company produced an average of 2,000 products [#permalink] New post 17 Nov 2011, 15:33
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Question Stats:

64% (02:55) correct 36% (01:43) wrong based on 174 sessions
During 2005, a company produced an average of 2,000 products per month. How many products will the company need to produce from 2006 through 2008 in order to increase its monthly average for the period from 2005 through 2008 by 200% over its 2005 average?

(A) 148,000
(B) 172,000
(C) 200,000
(D) 264,000
(E) 288,000
[Reveal] Spoiler: OA

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Last edited by Bunuel on 04 Aug 2012, 00:20, edited 2 times in total.
Renamed the topic and edited OA.
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Re: Monthly Average [#permalink] New post 17 Nov 2011, 16:17
The current average is 2,000/month and it's asking how many we'd have to produce from 2006 through 2008 to come to a final average from 2005-2008 of 200% more than that 2,000/month.

3(36{2,000}) = 24,000 + 24x... the left side of the equal sign gives me 300% (or 200% MORE) of the three-year total of the 2,000/month average. The right side of the equal sign gives me the 2005 production of 2,000/month plus the 2006-2008 ungiven average per month.

For some reason, though, my equation comes to x=8,000 and 8,000 each month for the 24 months of 2006-2008 is 192,000. Just another 8,000 short of the quota. I can't figure out where I'm messing up, but it's got to be something small.

Any idea anyone?
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Re: Monthly Average [#permalink] New post 21 Nov 2011, 03:30
I do not understand the problem. Is this from gmatprep ?
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Re: Monthly Average [#permalink] New post 21 Nov 2011, 05:52
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Company produced 12*2000 = 24,000 products in 2005. If company produces X products from 2006 to 2008, then total amount of product produced in 4 years (2005 through 2008) is X+24,000. The gives the average of (X+24,000)/4.

This average needs to be 200% higher than that in 2005. In math terms, 24,000+200%(24,000) = 72,000. So:

(X+24,000)/4 = 72,000
X+24,000 = 288,000
X = 264,000

The answer is D. Double check your OA.

To check our answer. Company produced 264,00 from 2006 through 2008 and 24,000 in 2005. That's a total of 288,000 in 4 years, that's 72,000 a year, that's 6,000 a month, which is 200% higher than 2,000.
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Re: Monthly Average [#permalink] New post 21 Nov 2011, 06:05
Four years! I can't believe I missed that. Should have gotten it. I was only figuring three years in 2005-2008. Ugh! Thanks, man.
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Re: Monthly Average [#permalink] New post 03 Aug 2012, 18:16
Bunnel

Can you please give a shorter method to do this please
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Re: Monthly Average [#permalink] New post 04 Aug 2012, 00:19
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venmic wrote:
Bunnel

Can you please give a shorter method to do this please


During 2005, a company produced an average of 2,000 products per month. How many products will the company need to produce from 2006 through 2008 in order to increase its monthly average for the period from 2005 through 2008 by 200% over its 2005 average?

(A) 148,000
(B) 172,000
(C) 200,000
(D) 264,000
(E) 288,000

200% more than 2,000 is 6,000 products per month.

Now, in order the monthly average, from 2005 through 2008, to be 6,000 products per month, the company should produce total of 6,000*48 products in these four years (48 months).

Since in 2005, the company produced total of 2,000*12 products, then from 2006 through 2008, the company should produce 6,000*48-2,000*12=2,000*12*(3*4-1)=2,000*12*11=264,000.

Answer: D.

Hope it's clear.
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Re: During 2005, a company produced an average of 2,000 products [#permalink] New post 06 Feb 2014, 13:23
jlgdr wrote:
During 2005, a company produced an average of 2,000 products per month. How many products will the company need to produce from 2006 through 2008 in order to increase its monthly average for the period from 2005 through 2008 by 200% over its 2005 average?

(A) 148,000
(B) 172,000
(C) 200,000
(D) 264,000
(E) 288,000


I was trying to solve this by differentials but couldn't. Would anybody tell me where I'm going wrong here?

OK so we have that 1 year, average is 2k
We need the total average to rise to 6k in the last 3 months

Therefore we have: -4(1) + 3x = 0

x = 4/3. Now this tells us that 4/3 should be the differential. Therefore 6 + 4/3 = 22/3 is supposed to be the key point. That is 22/3*1000, but it doesn't make any sense in the context of the answer choices

Many thanks
Hope its clear

Cheers
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Re: During 2005, a company produced an average of 2,000 products [#permalink] New post 27 Apr 2015, 06:32
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Re: During 2005, a company produced an average of 2,000 products [#permalink] New post 03 May 2015, 20:18
Bunuel wrote:
venmic wrote:
Bunnel

Can you please give a shorter method to do this please


During 2005, a company produced an average of 2,000 products per month. How many products will the company need to produce from 2006 through 2008 in order to increase its monthly average for the period from 2005 through 2008 by 200% over its 2005 average?

(A) 148,000
(B) 172,000
(C) 200,000
(D) 264,000
(E) 288,000

200% more than 2,000 is 6,000 products per month.

Now, in order the monthly average, from 2005 through 2008, to be 6,000 products per month, the company should produce total of 6,000*48 products in these four years (48 months).

Since in 2005, the company produced total of 2,000*12 products, then from 2006 through 2008, the company should produce 6,000*48-2,000*12=2,000*12*(3*4-1)=2,000*12*11=264,000.

Answer: D.

Hope it's clear.


perfect explanation.

concise, and deep and comprehensive explanation. you are a legendary of math section on gmat. it is great to have you here. your presence here is good for us
Re: During 2005, a company produced an average of 2,000 products   [#permalink] 03 May 2015, 20:18
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