During a 10-week summer vacation, was the average : DS Archive
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During a 10-week summer vacation, was the average

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During a 10-week summer vacation, was the average [#permalink]

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30 Jul 2007, 08:34
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During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

(1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week.
(2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.
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Re: DS: Summer Vacation [#permalink]

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30 Jul 2007, 11:05
sumande wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

(1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week.
(2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.

E.

1: 2c > (2a - 5)

if c = 5, and a = 5, 2c > (2a-5)
if c = 3, and a = 5, 2c > (2a-5)
if c = 6, and a = 5, 2c > (2a-5)

2: it says nothing.
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Re: DS: Summer Vacation [#permalink]

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30 Jul 2007, 19:58
Himalayan wrote:
sumande wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

(1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week.
(2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.

E.

1: 2c > (2a - 5)

if c = 5, and a = 5, 2c > (2a-5)
if c = 3, and a = 5, 2c > (2a-5)
if c = 6, and a = 5, 2c > (2a-5)

2: it says nothing.

Thanks Himalayan. I also came up with E, but the OA was A !! Guess, it must be wrong.
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30 Jul 2007, 20:50
Let number of books Carolyn reads be C
Let number of books Jacob reads be J

St1:
2(C/10) = 2(J/10)-5
(c/10) = (J/10)-5/2 <--- Carolyn reads less books per week on average
Sufficient.

St2:
Insufficient. We do not know who read more/less during the first five weeks.

Ans A
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30 Jul 2007, 21:34
ywilfred wrote:
Let number of books Carolyn reads be C
Let number of books Jacob reads be J

St1:
2(C/10) = 2(J/10)-5
(c/10) = (J/10)-5/2 <--- Carolyn reads less books per week on average
Sufficient.

St2:
Insufficient. We do not know who read more/less during the first five weeks.

Ans A

Statement 1 says "greater than", not "equal to".
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30 Jul 2007, 21:36
Himalayan wrote:
ywilfred wrote:
Himalayan wrote:
I did not get you, ywilfred.

which part?

how it is A?

okay, I see where you're going. I failed the read the part 'Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week.'

So the equation should be C/10 > J/10 + 5/2. So we can't solve for because C could be more or less than J. Error on my part. sorry everyone.
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30 Jul 2007, 21:48
E.

c > J - 2.5 == useless
St. 2 == even more useless (No wonder my verbal scores are showing a downward trend)
30 Jul 2007, 21:48
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During a 10-week summer vacation, was the average

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