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# During a 10-week summer vacation, was the average

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Director
Joined: 06 Jan 2008
Posts: 560
Followers: 2

Kudos [?]: 155 [0], given: 2

During a 10-week summer vacation, was the average [#permalink]  23 Apr 2008, 08:02
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
During a 10-week summer vacation, was the average (arithmetic mean) number of
books that Carolyn read per week greater than the average number of books that Jacob
(1) Twice the average number of books that Carolyn read per week was greater
than 5 less than twice the average number of books that Jacob read per week.
(2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more
than Jacob.
SVP
Joined: 24 Aug 2006
Posts: 2133
Followers: 3

Kudos [?]: 103 [0], given: 0

Re: DS - Carolyn [#permalink]  23 Apr 2008, 08:11
saravalli wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of
books that Carolyn read per week greater than the average number of books that Jacob
(1) Twice the average number of books that Carolyn read per week was greater
than 5 less than twice the average number of books that Jacob read per week.
(2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more
than Jacob.

First of all, this is a question testing averages, so it's at most a medium level question.

Let C = Caro's avg
Let J = Jacob's avg

a) 2C > 2J-5
b) Last 5 weeks is not enough information.

simple enough, and since it's an "at-most" medium level question, nothing tricky involved

I like A
Senior Manager
Joined: 19 Apr 2008
Posts: 323
Followers: 3

Kudos [?]: 48 [0], given: 0

Re: DS - Carolyn [#permalink]  23 Apr 2008, 16:19
For these kind of questions I will always try to plug in some values to make sure :

for S1 -

try c=4 , j=5 ; 2c>2j-5 is satisfied; c<j
try c=5 , j=4 ; 2c>2j-5 is satisfied; c>j

for S2 doesn't give any useful inforamation so answer is E . What is OA?
Director
Joined: 06 Jan 2008
Posts: 560
Followers: 2

Kudos [?]: 155 [0], given: 2

Re: DS - Carolyn [#permalink]  26 Apr 2008, 10:59
kidderek wrote:
saravalli wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of
books that Carolyn read per week greater than the average number of books that Jacob
(1) Twice the average number of books that Carolyn read per week was greater
than 5 less than twice the average number of books that Jacob read per week.
(2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more
than Jacob.

First of all, this is a question testing averages, so it's at most a medium level question.

Let C = Caro's avg
Let J = Jacob's avg

a) 2C > 2J-5
b) Last 5 weeks is not enough information.

simple enough, and since it's an "at-most" medium level question, nothing tricky involved

I like A

Can you please refer to rpmodi's explanation above.
Thanks
Senior Manager
Joined: 06 Aug 2007
Posts: 368
Followers: 1

Kudos [?]: 23 [0], given: 0

Re: DS - Carolyn [#permalink]  26 Apr 2008, 11:24
rpmodi wrote:
For these kind of questions I will always try to plug in some values to make sure :

for S1 -

try c=4 , j=5 ; 2c>2j-5 is satisfied; c<j
try c=5 , j=4 ; 2c>2j-5 is satisfied; c>j

for S2 doesn't give any useful inforamation so answer is E . What is OA?

I went for A too...rmodi..good explanation. I am with E now.
SVP
Joined: 24 Aug 2006
Posts: 2133
Followers: 3

Kudos [?]: 103 [0], given: 0

Re: DS - Carolyn [#permalink]  26 Apr 2008, 23:20
saravalli wrote:
kidderek wrote:
saravalli wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of
books that Carolyn read per week greater than the average number of books that Jacob
(1) Twice the average number of books that Carolyn read per week was greater
than 5 less than twice the average number of books that Jacob read per week.
(2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more
than Jacob.

First of all, this is a question testing averages, so it's at most a medium level question.

Let C = Caro's avg
Let J = Jacob's avg

a) 2C > 2J-5
b) Last 5 weeks is not enough information.

simple enough, and since it's an "at-most" medium level question, nothing tricky involved

I like A

Can you please refer to rpmodi's explanation above.
Thanks

I'm an ass.

A is insuff
Director
Joined: 06 Jan 2008
Posts: 560
Followers: 2

Kudos [?]: 155 [0], given: 2

Re: DS - Carolyn [#permalink]  27 Apr 2008, 08:58
I too went for A in my practice test. I felt exactly the same way!!
Thanks.
Re: DS - Carolyn   [#permalink] 27 Apr 2008, 08:58
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