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# During a 10-week summer vacation, was the average

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During a 10-week summer vacation, was the average [#permalink]  05 Jun 2008, 12:40
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During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week

2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.
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Re: DS:books [#permalink]  05 Jun 2008, 13:35
So I'm going to take a stab at this. I'd really like to hear how others solved this one. Quite new to GMATClub problem solving.

From Statement 1: I gathered the following equation

2C > 2J - 5
or
C > J - 2.5

c= avg number of books Carol read
j = avg number of books Jacob read

From this inequality, whatever number Carol read, the avg will always be greater then J?

i thought stmt 2 was insufficient

so i'm going with A
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Re: DS:books [#permalink]  05 Jun 2008, 14:10
puma wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week

2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.

2(C/10)>2(J/10)-5.

1: Ok lets say X=100 and Y=100. WEll the statment is true and we found that C =J.

We can also say that C=10000000000000000000000 J=100. Obviously C>J and the statement holds true.

Insuff.

2: tells us nothing about the other weeks.

Together, I am not convinced that this is sufficient.

We don't know anything about the first few weeks.
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Re: DS:books [#permalink]  05 Jun 2008, 15:31
puma wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week

2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.

I am going to say A..

Avg.C>Avg.J?

1) 2(Avg.C)>2(Avg.J)-5 ...clearly Avg.C>Avg.J...

Sufficient..

2) Avg.C=SumC/Number of booksC..
Avg.J=SumJ/Number of BooksJ..

10 weeks.. 5Weeks so 1/2 of Number of BooksC..

1/2NumberC=NumberJ+3..Insuff i dont know how many books they read in the earlier half of the 10 week..
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Re: DS:books [#permalink]  05 Jun 2008, 16:14
i see your point too. anyone know the correct AC?
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Re: DS:books [#permalink]  05 Jun 2008, 19:38
I am going for E. The first 5 weeks are unknown and they can turn around the situation
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Re: DS:books [#permalink]  05 Jun 2008, 22:53
i need a better explanation..this question seems simple enough.i am stumped..if i got this wrong..
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Re: DS:books [#permalink]  05 Jun 2008, 23:05
puma wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week

2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.

A.

a comparison between Avg number of books read per week has to be done. I dont think 10 weeks matter.

2C> 2J-5 since C and J will be positive, this should be sufficient.
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Re: DS:books [#permalink]  05 Jun 2008, 23:45
I also go along with A.
wht is the OA?
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Re: DS:books [#permalink]  06 Jun 2008, 00:26
fresinha12 wrote:
puma wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week

2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.

I am going to say A..

Avg.C>Avg.J?

1) 2(Avg.C)>2(Avg.J)-5 ...clearly Avg.C>Avg.J...

Sufficient..

2) Avg.C=SumC/Number of booksC..
Avg.J=SumJ/Number of BooksJ..

10 weeks.. 5Weeks so 1/2 of Number of BooksC..

1/2NumberC=NumberJ+3..Insuff i dont know how many books they read in the earlier half of the 10 week..

I think statement 1 is insufficient too. The following inequality requires some thought

C+2.5>J
The condition holds true say for the following two situations

C=5, J=6
5+2.5>6
C is not greater than J

C=8, J=6
8+2.5>6
C is greater than J

hence insufficient, since we cant conclusively determine whether C>J or not.

The answer is E
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Re: DS:books [#permalink]  06 Jun 2008, 04:55
IMO E is the correct answer

both the statements put together dont help
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Re: DS:books [#permalink]  06 Jun 2008, 06:02
fresinha12 wrote:
GMATBLACKBELT wrote:
puma wrote:
During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week

2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.

2(C/10)>2(J/10)-5.

1: Ok lets say X=100 and Y=100. WEll the statment is true and we found that C =J.

We can also say that C=10000000000000000000000 J=100. Obviously C>J and the statement holds true.

Insuff.

2: tells us nothing about the other weeks.

Together, I am not convinced that this is sufficient.

We don't know anything about the first few weeks.

what is X and Y?

Sorry I forgot to change those to C and J.
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Re: DS:books [#permalink]  06 Jun 2008, 07:03
shit..i see my mistake...

whoa..
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Re: DS:books [#permalink]  06 Jun 2008, 07:40
C>J-2.5

This equation can take for C either C=J+1 or C=J-1 which is absurd.
Can not decide which one is greater with (1) ..Option (2) gives information about last 5 weeks.
We dont how many books did Carolyn and jacob read for the first 5 weeks.

So both options are insufficient.
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Re: DS:books [#permalink]  07 Jun 2008, 02:00
what? I go with E too.

A can only be possible if equation is 2c>2j+5
but in our case, the equation is 2c>2J-5

What's d source?
Re: DS:books   [#permalink] 07 Jun 2008, 02:00
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