Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

During a 6·day local trade show, the least number of people [#permalink]

Show Tags

13 Dec 2012, 06:42

17

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

66% (02:46) correct
34% (01:55) wrong based on 768 sessions

HideShow timer Statistics

During a 6·day local trade show, the least number of people registered in a single day was 80. Was the average (arithmetic mean) number of people registered per day for the 6 days greater than 90 ?

(1) For the 4 days with the greatest number of people registered, the average (arithmetic mean) number registered per day was 100. (2) For the 3 days with the smallest number of people registered, the average (arithmetic mean) number registered per day was 85.

During a 6·day local trade show, the least number of people registered in a single day was 80. Was the average (arithmetic mean) number of people registered per day for the 6 days greater than 90 ?

The question basically asks whether more than 6*90=540 people registered during the show.

(1) For the 4 days with the greatest number of people registered, the average (arithmetic mean) number registered per day was 100 --> in these 4 days total of 4*100=400 people registered. Since the minimum number of people registered on the other two days is 80*2=160, then the total number of people registered is at least 400+160=560. Sufficient.

(2) For the 3 days with the smallest number of people registered, the average (arithmetic mean) number registered per day was 85. Clearly insufficient. Consider: {85, 85, 85, 86, 86, 86} and {85, 85, 85, 1,000, 1,000, 1,000}.

The question says that the least number of people registered in a single day was 80. So do we have to consider 80 to be the least value on only one day or all 6 days ? The solution given in OG takes it for one day, 80+a+b+c+d+e/6.

Please guide me. I think I am a little lost in the wording of the question.

It actually doesn't matter! All you know is that the lowest number of people to ever register was 80. So, there was at least one day where exactly 80 people registered, and there were no days where fewer than 80 people registered. The other days could have had 80 registrants, or any number of registrants greater than 80. That's why the other five days are represented as variables - you can't really say much about them, until you get to the statements.

You could argue about whether 'least' implies that there was exactly one day with 80 registrants, but it isn't important to the solution.

And if they wanted to specifically say that exactly 80 people registered on every day, they'd have to state that clearly. Since they don't, you can't make that assumption.
_________________

Chelsey Cooley | Manhattan Prep Instructor | Seattle and Online

Re: During a 6·day local trade show, the least number of people [#permalink]

Show Tags

13 Jan 2014, 06:59

1

This post received KUDOS

Walkabout wrote:

During a 6·day local trade show, the least number of people registered in a single day was 80. Was the average (arithmetic mean) number of people registered per day for the 6 days greater than 90 ?

(1) For the 4 days with the greatest number of people registered, the average (arithmetic mean) number registered per day was 100. (2) For the 3 days with the smallest number of people registered, the average (arithmetic mean) number registered per day was 85.

Basically, they're both telling us that there's AT LEAST 480 people in total, for all days, and they're asking us if there were more than 540 people registered, in total.

1) 4* 100 = 400, + the smallest value which is 80. And since we know that the 6:th value has to be greater than 80, then we know that more than 540 people were registered. So 1) is sufficient

2) This only tells us that more than 255 people were registered, but this gives us no further insight in if total people registered is > 540.. So insufficient

Re: During a 6·day local trade show, the least number of people [#permalink]

Show Tags

27 Dec 2012, 07:50

(2) For the 3 days with the smallest number of people registered, the average (arithmetic mean) number registered per day was 85. Clearly insufficient. Consider: {85, 85, 85, 86, 86, 86} and {85, 85, 85, 1,000, 1,000, 1,000}.

Answer: A.[/quote]

Bunuel,

From my understanding. It says the first 3 days the avg is 85. IT does not talk about the other 3 days. It can vary from 80 to anything. So is there any specific reason you wrote {85, 85, 85, 86, 86, 86}??
_________________

I've failed over and over and over again in my life and that is why I succeed--Michael Jordan Kudos drives a person to better himself every single time. So Pls give it generously Wont give up till i hit a 700+

Re: During a 6·day local trade show, the least number of people [#permalink]

Show Tags

20 Feb 2013, 18:40

rajathpanta wrote:

(2) For the 3 days with the smallest number of people registered, the average (arithmetic mean) number registered per day was 85. Clearly insufficient. Consider: {85, 85, 85, 86, 86, 86} and {85, 85, 85, 1,000, 1,000, 1,000}.

Answer: A.

Bunuel,

From my understanding. It says the first 3 days the avg is 85. IT does not talk about the other 3 days. It can vary from 80 to anything. So is there any specific reason you wrote {85, 85, 85, 86, 86, 86}??[/quote]

Hi,

I might be able to help you there. You were right in saying that the values can range from 85 to anything. However, it cannot be 85 since three days with the least value have already been mentioned. Let's take the immediate bigger value=86. Similarly since it can range to anything you can take 100,000 as the upper limit. This might be the reason that Bunuel took those examples.

In such questions, it might help you to test extreme cases or cases that might result in the option yielding both yes and no answers.

During a 6-day local trade show, the least number of people registered [#permalink]

Show Tags

10 Dec 2014, 17:02

During a 6-day local trade show, the least number of people registered in a single day was 80. Was the average (arithmetic mean) number of people registered per day for the 6 days greater than 90? (1) For the 4 days with the greatest number of people registered, the average (arithmetic mean) number registered per day was 100. (2) For the 3 days with the smallest number of people registered, the average (arithmetic mean) number registered per day was 85.
_________________

Re: During a 6-day local trade show, the least number of people registered [#permalink]

Show Tags

10 Dec 2014, 17:15

it has been given that least number of people registered per day was 80 Option 1: The total number of people registered for 4 days will be 400. So the average will be 400+80(least no of people)+81(>80)/6=561(>)/6=90+(>) .Sufficient

Option 2: The total number of people registered for 3 days with least people is 255. total number of people for 2 days is 255-80=175 leaves us the option of 87 and 88 people attending for other 2 days.(keeping the maximum of 2 days minimum ). Assume other 3 days attendance was 89 per each day or 95 per each day. Since different value yield a different result this option is not sufficient

Re: During a 6-day local trade show, the least number of people registered [#permalink]

Show Tags

10 Dec 2014, 18:52

kukr007 wrote:

During a 6-day local trade show, the least number of people registered in a single day was 80. Was the average (arithmetic mean) number of people registered per day for the 6 days greater than 90? (1) For the 4 days with the greatest number of people registered, the average (arithmetic mean) number registered per day was 100. (2) For the 3 days with the smallest number of people registered, the average (arithmetic mean) number registered per day was 85.

The question "Was the average (arithmetic mean) number of people registered per day for the 6 days greater than 90?" can be rewritten as "Was the total number of people registered for the 6 days greater than 540?".

Statement 1: the total number of people during the 4 days was 400. The least number of people in a single day was 80. The total number of people during the 5 days was 480. The 6th day has to be between 80 and 100. Therefore, total sum ranges from 560 to 580, both of which greater than 540. Statement 1 is sufficient.

Statement 2: the total number of people during the 3 days was 255 and this figure includes the day with the least number of people. The sum of the number of people during the remaining 3 days must be greater than 285, meaning, on average, there should be more than 95 people attending the the local trade show per day. Note that the total number of people during the 3 days was 255. If day with the least number of people was excluded, the sum of the number of people during the 2 days would be 175, implying an average of 87.5 people per day or more. This number could be either greater or lower than 95. Therefore, statement 2 is insufficient.

During a 6-day local trade show, the least number of people registered in a single day was 80. Was the average (arithmetic mean) number of people registered per day for the 6 days greater than 90? (1) For the 4 days with the greatest number of people registered, the average (arithmetic mean) number registered per day was 100. (2) For the 3 days with the smallest number of people registered, the average (arithmetic mean) number registered per day was 85.

Merging topics. Please search before posting. Thank you.
_________________

Re: During a 6·day local trade show, the least number of people [#permalink]

Show Tags

20 Aug 2015, 13:05

Bunuel wrote:

During a 6·day local trade show, the least number of people registered in a single day was 80. Was the average (arithmetic mean) number of people registered per day for the 6 days greater than 90 ?

The question basically asks whether more than 6*90=540 people registered during the show.

(1) For the 4 days with the greatest number of people registered, the average (arithmetic mean) number registered per day was 100 --> in these 4 days total of 4*100=400 people registered. Since the minimum number of people registered on the other two days is 80*2=160, then the total number of people registered is at least 400+160=560. Sufficient.

(2) For the 3 days with the smallest number of people registered, the average (arithmetic mean) number registered per day was 85. Clearly insufficient. Consider: {85, 85, 85, 86, 86, 86} and {85, 85, 85, 1,000, 1,000, 1,000}.

Answer: A.

Hi Bunuel, in your answers I have marked 85 because it cannot be 85.. the minimum value is 80, in this case we're left with 175 (3*85-80) and we have 2 scenarios for statement 2: 1. (min) [80,87,88 then the values for each of the remaining 3 days =>88 --> {80,81,88,88,88,88} Average = 85,5 2. (max) {80,81,94,1000,1000,1000 --> Average >90
_________________

When you’re up, your friends know who you are. When you’re down, you know who your friends are.

Share some Kudos, if my posts help you. Thank you !

Re: During a 6·day local trade show, the least number of people [#permalink]

Show Tags

19 Sep 2016, 10:02

The question says that the least number of people registered in a single day was 80. So do we have to consider 80 to be the least value on only one day or all 6 days ? The solution given in OG takes it for one day, 80+a+b+c+d+e/6.

Please guide me. I think I am a little lost in the wording of the question.

Re: During a 6·day local trade show, the least number of people [#permalink]

Show Tags

20 Sep 2016, 22:03

Thanks ccooley. Now I understand the rationale behind taking 80 as the least number of registrations for all 6 days. As 80 is the least number to ever register, the sum of registrations on other five days would be greater than or equal to 400.

gmatclubot

Re: During a 6·day local trade show, the least number of people
[#permalink]
20 Sep 2016, 22:03

Happy New Year everyone! Before I get started on this post, and well, restarted on this blog in general, I wanted to mention something. For the past several months...

It’s quickly approaching two years since I last wrote anything on this blog. A lot has happened since then. When I last posted, I had just gotten back from...

Post-MBA I became very intrigued by how senior leaders navigated their career progression. It was also at this time that I realized I learned nothing about this during my...