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During a certain week, a seal ate 50% of the first 80 smelt [#permalink]
24 May 2013, 14:44

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Difficulty:

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Question Stats:

63% (02:36) correct
37% (01:49) wrong based on 131 sessions

During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?

Re: During a certain week, a seal ate 50% of the first 80 smelt [#permalink]
24 May 2013, 14:50

Expert's post

pikachu wrote:

During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?

Re: During a certain week, a seal ate 50% of the first 80 smelt [#permalink]
25 May 2013, 02:34

Bunuel wrote:

pikachu wrote:

During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?

Re: During a certain week, a seal ate 50% of the first 80 smelt [#permalink]
25 May 2013, 02:37

Expert's post

nikhilsehgal wrote:

Bunuel wrote:

pikachu wrote:

During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?

Re: During a certain week, a seal ate 50% of the first 80 smelt [#permalink]
23 May 2014, 01:45

Hi,

I am getting a different answer. My approach: 1. First Part - 80 smelts - 50% eaten = 40 ....... Statement 1 2. 2nd Part - x smelts - 30% eaten = 0.3x ....... Statement 2

Total Smelts = 1st part + 2nd part = 80+x Seal ate 40% of total smelts => 0.4 (80+x) ....... Statement 3

Therefore , combining Statement 1,2,3 40 + 0.3x = 0.4(80+x) . This is giving x = 80 and 32 as the answer.

Re: During a certain week, a seal ate 50% of the first 80 smelt [#permalink]
23 May 2014, 02:04

Expert's post

mayankgc wrote:

During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?

A. 32 B. 40 B. 55 D. 64 E. 80

Hi,

I am getting a different answer. My approach: 1. First Part - 80 smelts - 50% eaten = 40 ....... Statement 1 2. 2nd Part - x smelts - 30% eaten = 0.3x ....... Statement 2

Total Smelts = 1st part + 2nd part = 80+x Seal ate 40% of total smelts => 0.4 (80+x) ....... Statement 3

Therefore , combining Statement 1,2,3 40 + 0.3x = 0.4(80+x) . This is giving x = 80 and 32 as the answer.

Kindly assist where I have gone wrong. Thanks

We are told that the seal ate 30% of the remaining smelt it came across. Thus x in your solution must be the number of the remaining smelt. Which makes the total number of smelt equal to 80 + x = 160. 40% of 160 is 64.

Re: During a certain week, a seal ate 50% of the first 80 smelt [#permalink]
25 May 2014, 22:25

Expert's post

pikachu wrote:

During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?

A. 32 B. 40 B. 55 D. 64 E. 80

Responding to a pm:

The seal ate 50% of first portion and 30% of second portion. Overall (average), it ate 40% of the entire portion.

Using scale method, Second portion/First portion = (50 - 40)/(40 - 30) = 1/1

So both portions need to be equal i.e. of 80 smelts each. So both portions together had 160 smelts and the seal ate 40% of it i.e. (40/100)*160 = 64 smelts _________________