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During a certain week, XYZ ate 50 percent of the first 80

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Director
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During a certain week, XYZ ate 50 percent of the first 80 [#permalink] New post 14 May 2007, 19:46
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During a certain week, XYZ ate 50 percent of the first 80 banana it came across, and 30 percent of the remaining banana it came across. If XYZ ate 40 percent of the banana it came across during the entire week, how many banana did it eat?


32
40
55
64
80
Director
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 [#permalink] New post 14 May 2007, 20:25
D. 64

X => total babana.

0.5*80+0.3*(X-80) = 0.4*X =>X=160
banana it ate =>.5*80+.3*(160-80) = 64
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 [#permalink] New post 14 May 2007, 20:28
80 is the answer
x is the remainding number of bananas

0.5*80+0.3x=0.4(80+x)

x=80

40+0.3*80=64

64 is the answer
  [#permalink] 14 May 2007, 20:28
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During a certain week, XYZ ate 50 percent of the first 80

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