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# During a sale, a clothing store sold each shirt at a price

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Manager
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During a sale, a clothing store sold each shirt at a price [#permalink]

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02 Oct 2006, 20:26
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During a sale, a clothing store sold each shirt at a price of 15$and each sweater at a price of 25$. Did the store sell more sweaters than shirts during the sale?

(1) The average (arithmetic mean) of the prices of all the shirts and sweaters that the store sold during the sale was $21. (2) The total of the prices of all the shirts and sweaters that the store sold during the sale was$420.
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ARISE AWAKE AND REST NOT UNTIL THE GOAL IS ACHIEVED

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02 Oct 2006, 21:46
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I go for A. u can get the ratio out of the equation, so it is sufficient.
but 2) is not enough.
Manager
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05 Oct 2006, 20:33
Could you please explain a bit more, of how we can get the ratio..

The only equation I could get with A is

(15* shirts number + 25 * sweaters number)/ (shirts number + sweaters number) = 21
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ARISE AWAKE AND REST NOT UNTIL THE GOAL IS ACHIEVED

Director
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05 Oct 2006, 20:44
D

Statement 1:
No of shirts = x
No of sweaters = y

(15x+25Y)/(x+y) = 21

Simplifying,
6X=4Y. So, 6 shirts were sold for every 4 sweaters sold. SUFF

Statement 2:
15x+25y = 420
Divide throughout by 5 to get
3x+5y = 84

The only positive integers that satisfy this equation are x=8 and y=12. SUFF
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06 Oct 2006, 02:39
anandsebastin wrote:
D

Statement 1:
No of shirts = x
No of sweaters = y

(15x+25Y)/(x+y) = 21

Simplifying,
6X=4Y. So, 6 shirts were sold for every 4 sweaters sold. SUFF

Statement 2:
15x+25y = 420
Divide throughout by 5 to get
3x+5y = 84

The only positive integers that satisfy this equation are x=8 and y=12.
SUFF

Hey anandsebastin, u r mistaken

3x+5y = 84

x=8 and y = 12 is one solution x<y
x=18 and y = 6 is another solution x>y

So statement 2 is not sufficient..........

It is clear that A is the answer.........
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06 Oct 2006, 07:57
One more for A...(educated guess).

The mean of 15 and 25 is 20. So if the mean price is 21 of all the shirts/sweaters sold then a little more of the \$21 items were sold.
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06 Oct 2006, 13:21
folks i cant get it help??????????
Intern
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06 Oct 2006, 16:43
I think it's C

x - shirt, y - sweater
Have to find if x>y

1) (15x + 25y)/(x + y) = 21
or 3x = 2y
Not suff

2) 15x + 25y = 420
3x + 5y = 84
Not suff

Using 1 and 2:
7y = 84 or y = 12 and x = 8

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06 Oct 2006, 16:45
My mistake it's A
Manager
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07 Oct 2006, 17:58
D-dude wrote:
I think it's C

x - shirt, y - sweater
Have to find if x>y

1) (15x + 25y)/(x + y) = 21
or 3x = 2y
Not suff

2) 15x + 25y = 420
3x + 5y = 84
Not suff

Using 1 and 2:
7y = 84 or y = 12 and x = 8

Hey dude..ur equation 3x=2y can be simplified as y=1.5x, so A is sufficient..dont u think so...

gud explanation Anand, cicerone and matrix(gud educated guess, i too thot of the same, but didnt have a solid solution backing it up)
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ARISE AWAKE AND REST NOT UNTIL THE GOAL IS ACHIEVED

Manager
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07 Oct 2006, 18:01
And time for the OA..

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OA is A, and it's from Gmatprep
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ARISE AWAKE AND REST NOT UNTIL THE GOAL IS ACHIEVED

07 Oct 2006, 18:01
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