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# During a sale, a clothing store sold each shirt at a price

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Manager
Joined: 11 Jan 2006
Posts: 230
Location: Arkansas, US
WE 1: 2.5 yrs in manufacturing
Followers: 1

Kudos [?]: 10 [0], given: 18

During a sale, a clothing store sold each shirt at a price [#permalink]  02 Oct 2006, 20:26
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
During a sale, a clothing store sold each shirt at a price of 15$and each sweater at a price of 25$. Did the store sell more sweaters than shirts during the sale?

(1) The average (arithmetic mean) of the prices of all the shirts and sweaters that the store sold during the sale was $21. (2) The total of the prices of all the shirts and sweaters that the store sold during the sale was$420.
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ARISE AWAKE AND REST NOT UNTIL THE GOAL IS ACHIEVED

VP
Joined: 25 Jun 2006
Posts: 1173
Followers: 2

Kudos [?]: 79 [0], given: 0

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I go for A. u can get the ratio out of the equation, so it is sufficient.
but 2) is not enough.
Manager
Joined: 11 Jan 2006
Posts: 230
Location: Arkansas, US
WE 1: 2.5 yrs in manufacturing
Followers: 1

Kudos [?]: 10 [0], given: 18

Could you please explain a bit more, of how we can get the ratio..

The only equation I could get with A is

(15* shirts number + 25 * sweaters number)/ (shirts number + sweaters number) = 21
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ARISE AWAKE AND REST NOT UNTIL THE GOAL IS ACHIEVED

Director
Joined: 23 Jun 2005
Posts: 847
GMAT 1: 740 Q48 V42
Followers: 5

Kudos [?]: 36 [0], given: 1

D

Statement 1:
No of shirts = x
No of sweaters = y

(15x+25Y)/(x+y) = 21

Simplifying,
6X=4Y. So, 6 shirts were sold for every 4 sweaters sold. SUFF

Statement 2:
15x+25y = 420
Divide throughout by 5 to get
3x+5y = 84

The only positive integers that satisfy this equation are x=8 and y=12. SUFF
Senior Manager
Joined: 28 Aug 2006
Posts: 302
Followers: 10

Kudos [?]: 99 [0], given: 0

anandsebastin wrote:
D

Statement 1:
No of shirts = x
No of sweaters = y

(15x+25Y)/(x+y) = 21

Simplifying,
6X=4Y. So, 6 shirts were sold for every 4 sweaters sold. SUFF

Statement 2:
15x+25y = 420
Divide throughout by 5 to get
3x+5y = 84

The only positive integers that satisfy this equation are x=8 and y=12.
SUFF

Hey anandsebastin, u r mistaken

3x+5y = 84

x=8 and y = 12 is one solution x<y
x=18 and y = 6 is another solution x>y

So statement 2 is not sufficient..........

It is clear that A is the answer.........
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Senior Manager
Joined: 13 Sep 2006
Posts: 282
Location: New York
Followers: 1

Kudos [?]: 8 [0], given: 0

One more for A...(educated guess).

The mean of 15 and 25 is 20. So if the mean price is 21 of all the shirts/sweaters sold then a little more of the \$21 items were sold.
SVP
Joined: 05 Jul 2006
Posts: 1516
Followers: 5

Kudos [?]: 127 [0], given: 39

folks i cant get it help??????????
Intern
Joined: 05 Oct 2006
Posts: 15
Followers: 0

Kudos [?]: 0 [0], given: 0

I think it's C

x - shirt, y - sweater
Have to find if x>y

1) (15x + 25y)/(x + y) = 21
or 3x = 2y
Not suff

2) 15x + 25y = 420
3x + 5y = 84
Not suff

Using 1 and 2:
7y = 84 or y = 12 and x = 8

Intern
Joined: 05 Oct 2006
Posts: 15
Followers: 0

Kudos [?]: 0 [0], given: 0

My mistake it's A
Manager
Joined: 11 Jan 2006
Posts: 230
Location: Arkansas, US
WE 1: 2.5 yrs in manufacturing
Followers: 1

Kudos [?]: 10 [0], given: 18

D-dude wrote:
I think it's C

x - shirt, y - sweater
Have to find if x>y

1) (15x + 25y)/(x + y) = 21
or 3x = 2y
Not suff

2) 15x + 25y = 420
3x + 5y = 84
Not suff

Using 1 and 2:
7y = 84 or y = 12 and x = 8

Hey dude..ur equation 3x=2y can be simplified as y=1.5x, so A is sufficient..dont u think so...

gud explanation Anand, cicerone and matrix(gud educated guess, i too thot of the same, but didnt have a solid solution backing it up)
_________________

ARISE AWAKE AND REST NOT UNTIL THE GOAL IS ACHIEVED

Manager
Joined: 11 Jan 2006
Posts: 230
Location: Arkansas, US
WE 1: 2.5 yrs in manufacturing
Followers: 1

Kudos [?]: 10 [0], given: 18

And time for the OA..

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OA is A, and it's from Gmatprep
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ARISE AWAKE AND REST NOT UNTIL THE GOAL IS ACHIEVED

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