Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

During a trip, Francine traveled x percent of the total [#permalink]
05 Sep 2004, 06:17

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

During a trip, Francine traveled x percent of the total distance at an average speed of 40 miles per hour and the rest of the distance at an average speed of 60 miles per hour. In terms of x, what was Francineâ€™s average speed for the entire trip?

i am with hardworking on this one. I think the individual who posted forgot to include the final zero on answer E. I plugged in and said that the traveler drove 50%,x, of 120 miles trip at 40 mph and the other half at 60 mph. Therefore the total traveling time was 2.5 hours for 120 miles and the average speed was 48 mph. C comes close but if you add another zero to E, then 250x48=12,000.

My explanation: Let the total distance traveled be A.
First Section: Distance = xA/100, Speed = 40, Time = xA/4000
Second Section: Distance = A(100-x)/100, Speed = 60, Time = A(100-x)/6000

Total journey: Distance = A, Time = [xA/4000+ A(100-x)/6000]
Ave. Speed = [A] / [xA/4000+ A(100-x)/6000]
= 12000/(x+200).

Recheck: For checking back, lets say he travelled a total distance of (A=) 60 miles, and x = 25%
First Section: Distance = 15, Speed = 40, Time = 15/40
Second Section: Distance = 45, Speed = 60, Time = 45/60
Total journey: Distance = 60, Time = 135/120, Ave. Speed = 160/3
Substitute x=25 in 12000/(x+200), you get 160/3

PS: I had initially taken total distance to be 100 for simplicity in calculation. But took a generic distance of A, just to prove the point.

Well, you're assuming x to be in 100 percentage points. Although that's not what the question said, as long as you're explicitly saying that x is in 100 percentage point, your formula will be correct.

You can get my formula from yours by noticing that x is in 100 percentage points in your formula and dividing the numerator and denominator by 100. My formula is in percent/proportions. That's the only difference.

i am with hardworking on this one. I think the individual who posted forgot to include the final zero on answer E. I plugged in and said that the traveler drove 50%,x, of 120 miles trip at 40 mph and the other half at 60 mph. Therefore the total traveling time was 2.5 hours for 120 miles and the average speed was 48 mph. C comes close but if you add another zero to E, then 250x48=12,000.

OOPS!, my mistake , yes it is 12000 and the answer is E infact (1200/x+200)