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during a trip on an expressway, Don drove a total of x

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during a trip on an expressway, Don drove a total of x [#permalink] New post 27 Jan 2006, 16:35
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during a trip on an expressway, Don drove a total of x miles. His average speed on a certain 5-mile section of the expressway was 30 miles per hour, and his average speed for the remainder of the trip was 60 miles per hour. His travel time for the x-mile trip was what percent greater than it would have been if he had traveled at a constant rate of 60 miles per hour for the entire trip?

8.5 %
50 %
x/12 %
60/x %
500 %
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 [#permalink] New post 27 Jan 2006, 17:07
[5/30+((x-5)/60)-x/60]/(x/60)

My answer is 500/x%
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 [#permalink] New post 27 Jan 2006, 19:41
total dist = x miles

time take to clear 5 mile section at 30miles/hr = 5/30 = 1/6 hr

time taken to clear x-5 miles section at 60 miles/hr = x-5/60 hr

Total time = 1/6 + x-5/60 = x+5/60 hr

Total time to clear x miles if he traveled at constant rate of 60 miles/hr = x/60 hr

Extra time = 5/60 = 1/12 hr

Percentage greater = (1/12)/(x/60) * 100% = 500/x %
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 [#permalink] New post 27 Jan 2006, 22:57
Total distance X miles

Time taken to travel distance X at 60 mph X/60 …………..1

Time taken to travel distance X-5 at 30mph (X-5)/30 …………….2

Percentage of time taken with case2 compared to case 1.
( 1-2)/1. = 500%
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reloading NEURON JELLY to reach another galaxy.

  [#permalink] 27 Jan 2006, 22:57
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during a trip on an expressway, Don drove a total of x

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