Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
It appears that you are browsing the GMAT Club forum unregistered!
Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club
Registration gives you:
Tests
Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.
Applicant Stats
View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more
Books/Downloads
Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
E, F, G, and H are the vertices of a polygon. Is polygon [#permalink]
28 Nov 2010, 12:18
6
This post was BOOKMARKED
00:00
A
B
C
D
E
Difficulty:
25% (medium)
Question Stats:
61% (01:23) correct
39% (00:25) wrong based on 230 sessions
E, F, G, and H are the vertices of a polygon. Is polygon EFGH a square?
(1) EFGH is a parallelogram.
(2) The diagonals of EFGH are perpendicular bisectors of one another.
I answered B to this question.
Statement 1 is to broad. A parallelogram can be several things
Statement 2 correctly identifies this polygon as a rhombus. If this polygon is a rhombus then it IS NOT a square. By identifying the polygon as a rhombus doesn't this prove that the polygon EFGH IS NOT a square?
Re: DS Geometry Problem from my MGMAT CAT Test [#permalink]
28 Nov 2010, 12:32
1
This post received KUDOS
Expert's post
jscott319 wrote:
E, F, G, and H are the vertices of a polygon. Is polygon EFGH a square?
(1) EFGH is a parallelogram.
(2) The diagonals of EFGH are perpendicular bisectors of one another.
I answered B to this question.
Statement 1 is to broad. A parallelogram can be several things
Statement 2 correctly identifies this polygon as a rhombus. If this polygon is a rhombus then it IS NOT a square. By identifying the polygon as a rhombus doesn't this prove that the polygon EFGH IS NOT a square?
I am providing the official answer. Please help!
Rhombus is a quadrilateral with all four sides equal in length. So, all squares are rhombuses but not vise-versa.
(1) EFGH is a parallelogram --> all squares are parallelograms but not vise-versa. Not sufficient.
(2) The diagonals of EFGH are perpendicular bisectors of one another --> EFGH is a rhombus --> all squares are rhombuses but not vise-versa. Not sufficient.
(1)+(2) EFGH is a rhombus (all rhombus are parallelogram). Again all squares are rhombuses but not vise-versa. Not sufficient.
Re: DS Geometry Problem from my MGMAT CAT Test [#permalink]
06 Nov 2012, 02:34
Bunuel wrote:
(2) The diagonals of EFGH are perpendicular bisectors of one another --> EFGH is a rhombus --> all squares are rhombuses but not vise-versa. Not sufficient.
(1)+(2) EFGH is a rhombus (all rhombus are parallelogram). Again all squares are rhombuses but not vise-versa. Not sufficient.
Bunuel - One doubt, If the diagonals of EFGH are perpendicular bisectors of one another then the 2 diagonals are of the same measure right? then it could be rectangle also because diagonals of rectangle are equal and bisect each other.....
Re: DS Geometry Problem from my MGMAT CAT Test [#permalink]
06 Nov 2012, 04:59
Expert's post
Jp27 wrote:
Bunuel wrote:
(2) The diagonals of EFGH are perpendicular bisectors of one another --> EFGH is a rhombus --> all squares are rhombuses but not vise-versa. Not sufficient.
(1)+(2) EFGH is a rhombus (all rhombus are parallelogram). Again all squares are rhombuses but not vise-versa. Not sufficient.
Bunuel - One doubt, If the diagonals of EFGH are perpendicular bisectors of one another then the 2 diagonals are of the same measure right? then it could be rectangle also because diagonals of rectangle are equal and bisect each other.....
Cheers
The diagonals of EFGH are perpendicular bisectors of one another, means that the diagonals cut one another into two equal parts at 90°. If a rectangle is not a square, then its diagonals do not cut each other at 90°.
Re: DS Geometry Problem from my MGMAT CAT Test [#permalink]
06 Nov 2012, 05:16
Bunuel wrote:
Jp27 wrote:
Bunuel wrote:
(2) The diagonals of EFGH are perpendicular bisectors of one another --> EFGH is a rhombus --> all squares are rhombuses but not vise-versa. Not sufficient.
(1)+(2) EFGH is a rhombus (all rhombus are parallelogram). Again all squares are rhombuses but not vise-versa. Not sufficient.
Bunuel - One doubt, If the diagonals of EFGH are perpendicular bisectors of one another then the 2 diagonals are of the same measure right? then it could be rectangle also because diagonals of rectangle are equal and bisect each other.....
Cheers
The diagonals of EFGH are perpendicular bisectors of one another, means that the diagonals cut one another into two equal parts at 90°. If a rectangle is not a square, then its diagonals do not cut each other at 90°.
Hope it's clear.
yes Bunuel totally clear! many thanks for all your responses.
Re: E, F, G, and H are the vertices of a polygon. Is polygon [#permalink]
11 Jul 2014, 00:34
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________
Re: E, F, G, and H are the vertices of a polygon. Is polygon [#permalink]
01 Jul 2015, 22:07
Bunuel wrote:
Rhombus is a quadrilateral with all four sides equal in length. So, all squares are rhombuses but not vise-versa.
(1) EFGH is a parallelogram --> all squares are parallelograms but not vise-versa. Not sufficient.
(2) The diagonals of EFGH are perpendicular bisectors of one another --> EFGH is a rhombus --> all squares are rhombuses but not vise-versa. Not sufficient.
(1)+(2) EFGH is a rhombus (all rhombus are parallelogram). Again all squares are rhombuses but not vise-versa. Not sufficient.
In 2, the diagonals are perpendicular bisectors could happen for a rhombus as well as a square right? Is that why we're saying it's Insufficient? As far as I know,diagonals are perpendicular bisectors of each other for square ,rhombus and even rectangles.Please correct me if I'm wrong.
Re: E, F, G, and H are the vertices of a polygon. Is polygon [#permalink]
01 Jul 2015, 23:52
1
This post received KUDOS
Expert's post
davesinger786 wrote:
Bunuel wrote:
Rhombus is a quadrilateral with all four sides equal in length. So, all squares are rhombuses but not vise-versa.
(1) EFGH is a parallelogram --> all squares are parallelograms but not vise-versa. Not sufficient.
(2) The diagonals of EFGH are perpendicular bisectors of one another --> EFGH is a rhombus --> all squares are rhombuses but not vise-versa. Not sufficient.
(1)+(2) EFGH is a rhombus (all rhombus are parallelogram). Again all squares are rhombuses but not vise-versa. Not sufficient.
In 2, the diagonals are perpendicular bisectors could happen for a rhombus as well as a square right? Is that why we're saying it's Insufficient? As far as I know,diagonals are perpendicular bisectors of each other for square ,rhombus and even rectangles.Please correct me if I'm wrong.
From (2) the figure can be a square or rhombus, yes.
Diagonals of a rectangle are bisectors of each other but not perpendicular to each other, unless of course it's a square. _________________
As I’m halfway through my second year now, graduation is now rapidly approaching. I’ve neglected this blog in the last year, mainly because I felt I didn’...
Perhaps known best for its men’s basketball team – winners of five national championships, including last year’s – Duke University is also home to an elite full-time MBA...
Hilary Term has only started and we can feel the heat already. The two weeks have been packed with activities and submissions, giving a peek into what will follow...