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# Each digit 1 through 5 is used exactly once to create a 5-di

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Current Student
Status: Never ever give up on yourself.Period.
Joined: 23 Aug 2012
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Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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07 Jan 2013, 06:55
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Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible?

(A) 48
(B) 66
(C) 72
(D) 78
(E) 90
[Reveal] Spoiler: OA

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Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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07 Jan 2013, 07:10
Total number of 5 digit numbers that can be formed = 5! = 120.
Total number of 5 digit numbers in which 3 and 4 are adjacent = 48. This can be calculated by taking 3 and 4 as a pair and considering positions where they can appear.
Number of 5 digit numbers in which 3 and 4 are not adjacent = Total number of 5 digit numbers - Total number of 5 digit numbers in which 3 and 4 are adjacent.
Ans = 120 - 48 = 72.
Veritas Prep GMAT Instructor
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Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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07 Jan 2013, 10:32
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Expert's post
daviesj wrote:
Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible?

(A) 48
(B) 66
(C) 72
(D) 78
(E) 90

Such questions are best solved using the complement approach. You need to find arrangements in which 3 and 4 are not adjacent. Instead, work on finding the arrangements in which they are together since it is much easier to do.

Number of arrangements using 5 distinct digits = 5!
Number of arrangements in which 3 and 4 are adjacent - consider 3 and 4 together as one group. Now you have 4 numbers/groups to arrange which can be done in 4! ways. In each of these arrangements, 3 and 4 can be arranged as 34 or 43. So we need to multiply 4! by 2 to give all arrangements where 3 and 4 are adjacent to each other e.g. 34251, 43251, 23415, 32415 ...
Number of arrangements in which 3 and 4 are not adjacent = 5! - 2*4! = 72

Check out my detailed post on this concept: http://www.veritasprep.com/blog/2011/10 ... ts-part-i/
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Manager Joined: 04 Oct 2011 Posts: 224 Location: India Concentration: Entrepreneurship, International Business GMAT 1: 440 Q33 V13 GMAT 2: 0 Q0 V0 GPA: 3 Followers: 0 Kudos [?]: 44 [0], given: 44 Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink] ### Show Tags 14 Jan 2013, 04:46 daviesj wrote: Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible? (A) 48 (B) 66 (C) 72 (D) 78 (E) 90 Total number of arrangements of 5 digit integer = 5! = 120 Let 3 and 4 be single digit like { 1 2 X 5 } This set arrangement is 4! = 24 As 3 and 4 can be interchanged between them 2(24) = 48 So 120-48 =72 Pls correct me if my solution is wrong! _________________ GMAT - Practice, Patience, Persistence Kudos if u like Manager Joined: 04 Jan 2013 Posts: 80 Followers: 0 Kudos [?]: 8 [0], given: 1 Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink] ### Show Tags 14 Jan 2013, 12:45 daviesj wrote: Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible? (A) 48 (B) 66 (C) 72 (D) 78 (E) 90 combinatorics and permutations eish..how do you guys make out on which way to use,whether combination or permutation,when you have such problem to solve?..when do you use permutation and when do you use combination? Posted from my mobile device Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 6827 Location: Pune, India Followers: 1917 Kudos [?]: 11919 [0], given: 221 Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink] ### Show Tags 14 Jan 2013, 20:50 chiccufrazer1 wrote: daviesj wrote: Each digit 1 through 5 is used exactly once to create a 5-digit integer. If the 3 and the 4 cannot be adjacent digits in the integer, how many 5-digit integers are possible? (A) 48 (B) 66 (C) 72 (D) 78 (E) 90 combinatorics and permutations eish..how do you guys make out on which way to use,whether combination or permutation,when you have such problem to solve?..when do you use permutation and when do you use combination? Posted from my mobile device Discussed this dilemma here: http://www.veritasprep.com/blog/2011/11 ... binations/ _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: Each digit 1 through 5 is used exactly once to create a 5-di [#permalink]

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28 Nov 2014, 05:51
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Re: Each digit 1 through 5 is used exactly once to create a 5-di   [#permalink] 28 Nov 2014, 05:51
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