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The way to do it is to try and break the units digit into numbers that satisfy the criterion that it should be the sum of a number and its double... i.e. x + 2x...

A satisfies, as 3 = 1 + 2, but 15 cannot be broken into such a form.
The next choice that satisfies is D; 9 = 3 + 6. Also, 12 can be written as (8+4)... Hence D

Re: PS: sum of 2 digit numbers [#permalink]
08 Aug 2006, 13:16

divide each answer choice by 3, the result must be 2 digit number and cannot be greater than 44. also the unit digit of the resulting 2 digit number cannot be greater than 4.

A. 153/3 = 51. no good.
B 150/3 = 50. again not.
C 137/3 = fraction doesnot work.
D 129/3 = 43. it works but let wait for E.
E 89/3 = fraction. same as C.

Re: PS: sum of 2 digit numbers [#permalink]
08 Aug 2006, 13:21

Professor wrote:

divide each answer choice by 3, the result must be 2 digit number and cannot be greater than 44. also the unit digit of the resulting 2 digit number cannot be greater than 4.

I am sorry... probably a dumb but please bear with me so, why are we diving these by 3?

Re: PS: sum of 2 digit numbers [#permalink]
08 Aug 2006, 14:09

u2lover wrote:

Professor wrote:

divide each answer choice by 3, the result must be 2 digit number and cannot be greater than 44. also the unit digit of the resulting 2 digit number cannot be greater than 4.

I am sorry... probably a dumb but please bear with me so, why are we diving these by 3?

probably you got it by the time you read this post.

the question says that H is half of G and G is divisible by 2. if so G = 2H
their sum = G + H = 2H + H = 3H

I remember a trick from last year, someone from kaplan had told me..whenever u see the "which of the following" type question..start with answer choices in the bottom, i.e d and e..

ok, so lets see

i picked answer choice D ...129..hmm...

sum=2X+x....so lets 129=3x, does it divide by 3 yes...x=43....i will keep the answer choice..i check 89..does it divide by 3..NO..so I am done...129 is my answer...

As a Kaplan instructor, I can tell you that that advice is not helpful. The correct answer is just as likely to be A as E. You should quickly look at all of the answers to see which is the easiest to evaluate/most promising.