|
Author |
Message |
|
TAGS:
|
|
|
Manager
Joined: 13 Oct 2004
Posts: 246
Followers: 1
Kudos [?]:
4
[0], given: 0
|
Each employee of Company Z is an employee of either division [#permalink]
 01 Aug 2005, 13:43
Question Stats:
0% (00:00) correct
 0% (00:00) wrong based on 0 sessions
Each employee of Company Z is an employee of either division X or Division Y, but not both. If each division has some part-time employees, is the ratio of full-time employees to the number of part-time employees greater for Divsion X than for Company Z?
1 - The ratio of the number of full time employees to the number of part time employees is less for Division Y than for Company Z.
2- More than half of the full-time employees of Company Z are employees of Divsion X, and more than half of the part time employees of Company Z are employees of Divsion Y.
|
|
|
|
|
|
|
Senior Manager
Joined: 04 May 2005
Posts: 287
Location: CA, USA
Followers: 1
Kudos [?]:
4
[0], given: 0
|
D
X for number of full time in X
Y ......... in Y
Z ......... in Z
Pz for all part-timer of Z
Px for all part-timer of X
Py for all part-timer of Y
Pz = Px + Py
from 1) => Pz/(X+Y) - Py/Y > 0
=> Pz*Y - Py*(X+Y) = Pz*Y -(Pz-Px)(X+Y) = -Pz*X + Px*(X+Y) > 0
to find if Px/X - Pz/(X+Y) > 0, we only need to find out if Px*(X+Y) - Pz*X > 0
we know this is true
from 2) => X+Y <2X and 2Px < Px+Py
therefore, (Px+Py)/(X+Y) > (Px+Py)/2x > 2Px/2X
that is: Pz/Z > Px/X
|
|
|
|
|
|
Manager
Joined: 13 Oct 2004
Posts: 246
Followers: 1
Kudos [?]:
4
[0], given: 0
|
OA is D.
Lots of calculations. Any one know of a simpler way to get to the answer?.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
close
