Each employee on a certain task force is either a manager or a director. What percent ofthe employees on the task force are directors?
(1) the average (arithematic mean) of the salary of the managers on the task force is $5,000 less than the average salary of all employees on the task force.
(2) the average (arithematic mean) of the salary of the directors on the task force is $15,000 greater than the average salary of all employees on the task force
My answer is C,
Obviously both conditions alone are insufficient..
So let us take a situation that combines both condition
Group avg of 10000
M for no of managers (Avg salary of 5000)
D for no of directors (Avg salary of 25000)
Now according to the conditons
(M*5000 + D*25000)/(M+D) = 10000
D/M = 1/3, so directors are 25% of the group.
If somethings wrong, Pl.let me know
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