changhiskhan wrote:

Each of the 25 balls in a certain box is either red, blue, or white and has a number from 1 to 10 painted on it. If one ball is to be selected at random from the box, what is the probability that the ball selected will either be white or have an even number painted on it?

1) The probability that the ball will both be white and have an even number painted on it is 0.

2) The probability that the ball will be white minus the probability that the ball will have an even number painted on it is 0.2.

Thanks in advance.

P(White or Even) = P(White) + P(Even) - P(White & Even)

st 1) P(White & Even) = 0 .. still dont know individual probabilities . Not sufficient

st 2) P(White) - P(Even) = 0.2

.. still dont know abouit the combined probability and also individual probabilities. Not sufficient

combinging also we cannot figure out P(White) + P(Even) as we cannot find out the number of white balls or the number of even balls

E