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Each of the cucumbers in 100 pounds of cucumbers is composed [#permalink]
06 Oct 2010, 10:52

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Each of the cucumbers in 100 pounds of cucumbers is composed of 99% water, by weight. After some of the water evaporates, the cucumbers are now 98% water by weight. What is the new weight of the cucumbers, in pounds?

Each of the cucumbers in 100 pounds of cucumbers is composed of 99% water, by weight. After some of the water evaporates, the cucumbers are now 98% water by weight. What is the new weight of the cucumbers, in pounds?

* 2 * 50 * 92 * 96 * 98

Any other approach to solve this question Thanks

Out of 100 pounds 99% or 99 pounds is water and 1 pound is non-water. After some water evaporates the cucumbers become 98% water and 2% of non-water, so now 1 pound of non-water composes 2% of cucucmbers, which means that the new weight of cucumbers is 1/0.02=50 pounds.

Hi Bunnel, Would it be possible explain your solution? For some reason I am not getting it that how cucumber will be 50 pound after reduction of 1% water. Thanks

Hi Bunnel, Would it be possible explain your solution? For some reason I am not getting it that how cucumber will be 50 pound after reduction of 1% water. Thanks

Before some of the water evaporates: 100 pounds of cucumbers is composed of 99% water (= 99 pounds of water) AND 1% non-water (= 1 pound of non-water);

After some of the water evaporates: 98% water by weight AND the same 1 pound of non-water, which did not evaporate. This 1 pound of non-water now composes 100%-98%=2% of the total weight of cucumbers. So, 1 pound = 2% of the total weight of cucumbers --> total weight of cucumbers = 1/0.02 = 50 pounds.

Re: Each of the cucumbers in 100 pounds of cucumbers is composed [#permalink]
12 May 2012, 01:57

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Expert's post

shrive555 wrote:

Each of the cucumbers in 100 pounds of cucumbers is composed of 99% water, by weight. After some of the water evaporates, the cucumbers are now 98% water by weight. What is the new weight of the cucumbers, in pounds?

A. 2 B. 50 C. 92 D. 96 E. 98

Responding to a pm:

There are two ways of getting to the answer here.

Method 1: Let's go forward to back. Say we have 98% mixture (2% pure cucumber extract and 98% water). Say, we also have plain water (100% water). If we mix these two, we get 100 pounds of 99% mixture (1% pure cucumber extract and 99% water). We want to find the amount of pure water that was mixed. (Usually, we are given two components and we have to mix them. This question does the opposite. It separates out the components of the mixture but overall it doesn't matter to us at all.)

The 98% mixture and the pure water must have been mixed in 1:1 ratio. Since total mixture is 100 pounds, the amount of pure water must be 50 pounds and the 98% mixture must have been 50 pounds. Answer (B)

Method 2: Another way to think about this problem: The amount of pure cucumber extract stays the same. Only the amount of water reduces. The amount of pure cucumber extract was 1 pound in the 99% mixture and it stayed 1 pound in the 98% mixture. In 100 pounds of 99% cucumber mix, this pure cucumber extract was 1% and in 98% cucumber mix, this same pure cucumber extract was 2% of the cucumber mix.

Say, the total weight of 98% cucumber mix is x pounds. 1 pound = (2/100)*x x = 50 pounds

The answer is a little un-intuitive since you don't expect so much water to disappear to just make it go down from 99% to 98% but instead, think that you need to make the amount of pure cucumber extract to go up from 1% to 2% i.e. you need it to double in proportion. For the same amount (1 pound) to be double in proportion, you need to reduce the total weight by half. _________________

Re: Each of the cucumbers in 100 pounds of cucumbers is composed [#permalink]
18 Apr 2014, 22:02

I don't think any formula is needed in such questions.

It is pure logic which governs these questions.

Approach:

When one thing is getting replaced or removed just CONCENTRATE on the CONCENTRATION of that thing.

Concentrate here on 'Water'

99 Pounds = Water 1 pound = non water

Let X be evaporated so that concentration changes to 98%

99 - X = Water in new thing = 98% of total

99-X = 98/100 (100 - X)

X=50 _________________

Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________

Re: Each of the cucumbers in 100 pounds of cucumbers is composed [#permalink]
27 May 2014, 13:30

VeritasPrepKarishma wrote:

shrive555 wrote:

Each of the cucumbers in 100 pounds of cucumbers is composed of 99% water, by weight. After some of the water evaporates, the cucumbers are now 98% water by weight. What is the new weight of the cucumbers, in pounds?

Re: Each of the cucumbers in 100 pounds of cucumbers is composed [#permalink]
27 May 2014, 20:03

Expert's post

ronr34 wrote:

VeritasPrepKarishma wrote:

shrive555 wrote:

Each of the cucumbers in 100 pounds of cucumbers is composed of 99% water, by weight. After some of the water evaporates, the cucumbers are now 98% water by weight. What is the new weight of the cucumbers, in pounds?

how did you get to the right side of "1/1"? Why did you state that both of the weights are the same?

The cucumbers left after some water has evaporated is 98% water. The evaporated water is 100% water. These two were mixed together in the original 100 pounds of cucumber. The original 100 pounds of cucumbers had 99% water.

The formula of the scale method gives us: So w1/w2 = (A2 - Aavg)/(Aavg - A1) A1 - Water concentration of cucumber leftover = 98% A2 - Water concentration of pure water = 100% w1 - weight of cucumber leftover w2 - weight of water

w1/w2 = (100 - 99)/(99 - 98) = 1/1

So we can say that the weight of cucumber leftover and weight of water should be the same i.e. they both must be 50 pounds each.

Re: Each of the cucumbers in 100 pounds of cucumbers is composed [#permalink]
28 May 2014, 10:24

1 portion is non water ---- 99 portions are water 1% 99% now after vaporization The 1 portion became 2% ------> we have to calculate 1 is 2% of what? x * 0.02= 1 ----> x= 100/2 ----> x=50 "the new whole. hope this one is simple enough!