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Each person who attended a company meeting was either a

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Each person who attended a company meeting was either a [#permalink]

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26 Apr 2012, 02:51
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Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both. If 62 percent of these who attended the meeting were stockholders and 47 percent were employees. What percent were stockholders, who were not employees?

A. 52
B. 53
C. 54
D. 55
E. 56
[Reveal] Spoiler: OA

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Re: Each person who attended a company meeting [#permalink]

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26 Apr 2012, 02:58
100 = 62 + 47 - n(SnE) [where n represents intersection]
=> n(SnE) = 9

=> Number who were only stockholders = n(S) - n(SnE) = 53 percent

Option (B)
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26 Apr 2012, 03:09
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monir6000 wrote:
Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both. If 62 percent of these who attended the meeting were stockholders and 47 percent were employees. What percent were stockholders, who were not employees?

A. 52
B. 53
C. 54
D. 55
E. 56

Total = Stockholders + Employees - Both;
100 = 62 + 47 - Both --> Both = 9;

Percent of stockholders, who were not employees is: Stockholders - Both = 62 - 9 =53.

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24 Aug 2015, 20:59
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Re: Each person who attended a company meeting was either a [#permalink]

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01 Dec 2015, 08:18
I came up with the same answer choice B, but my approach was slightly different!

47% were employees which shall cover those who were only employees and those who were both shareholders and employees.

Thus, the number of attendants who were only shareholders is 100% - 47% = 53%.

Correct me if I'm wrong please!!!
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Re: Each person who attended a company meeting was either a [#permalink]

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01 Dec 2015, 09:32
Charles_River wrote:
I came up with the same answer choice B, but my approach was slightly different!

47% were employees which shall cover those who were only employees and those who were both shareholders and employees.

Thus, the number of attendants who were only shareholders is 100% - 47% = 53%.

Correct me if I'm wrong please!!!

USe venn diagram , matter of 5 secods
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Re: Each person who attended a company meeting was either a [#permalink]

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20 Jul 2016, 04:13
Does anyone know how can we solve this question by using the matrix/table ? I'm having difficulties in drawing one.

Thanks for your help!
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28 Jul 2016, 12:02
HarveyKlaus wrote:
Does anyone know how can we solve this question by using the matrix/table ? I'm having difficulties in drawing one.

Thanks for your help!

HarveyKlaus Hope it helps. This is my first post!
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Re: Each person who attended a company meeting was either a [#permalink]

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29 Jul 2016, 09:42
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Here we can use some of our high school set theory =>
N(A U B) = 100=> N(A) = 62 ; N(B)=47
N(intersection) => 62+47-100=9
Only A=>62-9=>53
Smash B
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Re: Each person who attended a company meeting was either a   [#permalink] 29 Jul 2016, 09:42
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