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Each side of a certain parallelogram has length 6. if the

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Each side of a certain parallelogram has length 6. if the [#permalink] New post 02 Mar 2008, 00:26
Each side of a certain parallelogram has length 6. if the area of the
parallelogram is 18. Which of the following is the measure of one of its angles
in degrees ?
30
45
60
90
120
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Re: geo [#permalink] New post 02 Mar 2008, 01:58
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marcodonzelli wrote:
Each side of a certain parallelogram has length 6. if the area of the parallelogram is 18. Which of the following is the measure of one of its angles in degrees ?30 45 60 90 120


A. 30

the hight should be 3 to have the area 18. then it makes a triangle with 30:60:90 if we draw a perpendicular from one of the vertex of ther parrallaogram.  the triangle withh be of height = 3, hypoteneous is 6, and base 3sqrt3.two angles of the parrallogram are 30 degree each and rst 150 deg each.
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Re: geo [#permalink] New post 02 Mar 2008, 10:42
I mistook triangle area formulae (A=1/2ab*sinY) for parallelogram area one (A=ab*sinY).
A 30 is correct. Sorry.
18=6*6*sin a
sin(a)=1/2 so a=30
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Re: geo [#permalink] New post 02 Mar 2008, 10:48
UMB wrote:
I mistook triangle area formulae (A=1/2ab*sinY) for parallelogram area one (A=ab*sinY).
A 30 is correct. Sorry.
18=6*6*sin a
sin(a)=1/2 so a=30


OA is A. I don't have a math background. could someone tell me some quick rules with sin, cosin, to apply in these cases. I appreciate very much!
Re: geo   [#permalink] 02 Mar 2008, 10:48
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