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# EAMA SUCCESS % QUESTION

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Manager
Status: GMAT Preperation
Joined: 04 Feb 2010
Posts: 103
Concentration: Social Entrepreneurship, Social Entrepreneurship
GPA: 3
WE: Consulting (Insurance)
Followers: 2

Kudos [?]: 90 [0], given: 15

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14 Oct 2010, 00:12
00:00

Difficulty:

(N/A)

Question Stats:

20% (02:48) correct 80% (00:11) wrong based on 5 sessions

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How many liters of a 40% iodine solution need to be mixed with 35 liters of a 20% iodine solution to
create a 35% iodine solution?
a. 35
b. 49
c. 100
d. 105
e. 140
Retired Moderator
Joined: 02 Sep 2010
Posts: 805
Location: London
Followers: 93

Kudos [?]: 762 [0], given: 25

Re: EAMA SUCCESS % QUESTION [#permalink]

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14 Oct 2010, 00:30
vanidhar wrote:
How many liters of a 40% iodine solution need to be mixed with 35 liters of a 20% iodine solution to
create a 35% iodine solution?
a. 35
b. 49
c. 100
d. 105
e. 140

Lets say we need x liters.
After mixing we get (x+35) liters.

Total Iodine before = Total Iodine after
$$40%*x + 20%*35 = 35%*(x+35)$$
$$5%*x=35*15%$$
$$x=35*3=105$$

_________________
Manager
Joined: 08 Sep 2010
Posts: 233
Location: India
WE 1: 6 Year, Telecom(GSM)
Followers: 4

Kudos [?]: 183 [0], given: 21

Re: EAMA SUCCESS % QUESTION [#permalink]

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14 Oct 2010, 00:33
Suppose x litres of 40% iodine solution is required.Then total volume of resultant 35 % iodine solution will be (x+35) litres.
Considering the iodine content ...we can derive
(40x/100) + ((20*35)/100) = (x+35) *(35/100)
Solving we get x=105 Litre .Hence D is the answer.

Re: EAMA SUCCESS % QUESTION   [#permalink] 14 Oct 2010, 00:33
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