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# Easy one, but i liked the language imagine vodka and

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Easy one, but i liked the language imagine vodka and [#permalink]  04 Aug 2008, 11:04
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Easy one, but i liked the language imagine vodka and whiskey with orange and lime juice ... i remember my college days

A bar is creating a new signature drink. There are five possible alcoholic ingredients in the drink: rum, vodka, gin, peach schnapps, or whiskey. There are five possible non-alcoholic ingredients: cranberry juice, orange juice, pineapple juice, limejuice, or lemon juice. If the bar uses two alcoholic ingredients and two non-alcoholic ingredients, how many different drinks are possible?

A. 100
B. 25
C. 50
D. 75
E. 3600
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Re: PS BAR [#permalink]  04 Aug 2008, 11:11
jallenmorris wrote:
A

C_5^2 * C_5^2 = 100

same i got
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Re: PS BAR [#permalink]  04 Aug 2008, 11:14
What if we change it up by adding the following:

"The owner is a peculiar little !@#\$ and claims he can tell when one ingredient is added before another. With the same number of ingredients above, 2 non-alcoholic and 2 alcoholic drinks of the 5 of each, how many different flavors are possible?"
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Re: PS BAR [#permalink]  04 Aug 2008, 11:23
jallenmorris wrote:
A

C_5^2 * C_5^2 = 100

i think its less than 100.... i mean who on earth mixes rum with gin ... we should rule out "illegal" combinations..

just kidding, OA is A
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Re: PS BAR [#permalink]  04 Aug 2008, 19:02
durgesh79 wrote:
i mean who on earth mixes rum with gin

The people at TGIF, they invented the long island iced tea.
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Re: PS BAR [#permalink]  04 Aug 2008, 20:35
jallenmorris wrote:
A

C_5^2 * C_5^2 = 100

Can you expand on this explanation? Also, Is there a shortcut to finding this answer?
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Re: PS BAR [#permalink]  04 Aug 2008, 23:04
Number of comb. = 5C2*5C2 = 10*10 = 100
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Re: PS BAR [#permalink]  05 Aug 2008, 10:26
nmohindru wrote:
Number of comb. = 5C2*5C2 = 10*10 = 100

What does the "C" stand for here?

5(# of alcohol) C(??) 2(since we mix 2 drinks) * 5(# of n/a drink) C(??) 2(since we mix 2 drinks)

Am i understanding that part correctly?
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Re: PS BAR [#permalink]  05 Aug 2008, 10:35
droopy57 wrote:
nmohindru wrote:
Number of comb. = 5C2*5C2 = 10*10 = 100

What does the "C" stand for here?

5(# of alcohol) C(??) 2(since we mix 2 drinks) * 5(# of n/a drink) C(??) 2(since we mix 2 drinks)

Am i understanding that part correctly?

droopy57 : you may want to brush up your permutation and combination, please see this.
http://www.mansw.nsw.edu.au/members/ref ... no4yen.htm

in this question C is the formula for number of combinations of taking r things out of n things = nCr = n!/(r! * (n-r)!)
5C2 = 5!/3!*2! = 5*4*3!/2*1*3! = 20/2 = 10
Re: PS BAR   [#permalink] 05 Aug 2008, 10:35
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