Efrida and Frazer who live 10 miles apart, meet at a restaur : GMAT Problem Solving (PS)
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# Efrida and Frazer who live 10 miles apart, meet at a restaur

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Efrida and Frazer who live 10 miles apart, meet at a restaur [#permalink]

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06 Jan 2013, 08:16
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72% (02:37) correct 28% (01:27) wrong based on 92 sessions

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Efrida and Frazer who live 10 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home?

A. 6
B. 7
C. 8
D. 10
E. 11
[Reveal] Spoiler: OA

Last edited by Bunuel on 07 Jan 2013, 03:03, edited 1 time in total.
Renamed the topic and edited the question.
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07 Jan 2013, 01:32
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chiccufrazer1 wrote:
efrida and frazer who live 10 miles apart,meet at a restaurant that is directly north of efrida's home and directly east of frazer's home.if the restaurant is too miles closer to efrida's home,than to frazer's home,how many miles is the restaurant from frazer's home
A.6 B.7 C.8 D.10 E.11

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Please check the questions when posting and format them properly.

Efrida and Frazer who live 10 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home?

A. 6
B. 7
C. 8
D. 10
E. 11

It's a simple geometry problem. Look at the diagram below:
Attachment:

Restraunt.PNG [ 4.84 KiB | Viewed 1668 times ]
From above it follows that the restaurant is 8 miles from Frazer's home and 6 miles from Efrida's home.

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07 Jan 2013, 03:01
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thanks bunuel..i really appreciate on how you have solved the problem..i also used the same terms except for x +2 which i ended up using x-2 instead..i did use the pythagorean theorem but i ended up getting something like wrong and getting more confused

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07 Jan 2013, 09:53
I also did the same thing as frazer and got it wrong.
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07 Jan 2013, 11:02
bunuel i have noticed one thing on how your have illustrated the information given in the diagram..the diagram indicates frazer's home as directly west of the restaurant rather than as directly east..does the direction change anything at all?

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08 Jan 2013, 02:38
chiccufrazer1 wrote:
bunuel i have noticed one thing on how your have illustrated the information given in the diagram..the diagram indicates frazer's home as directly west of the restaurant rather than as directly east..does the direction change anything at all?

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The stem says that the restaurant is directly east of Frazer's home, hence Frazer's home is directly west of the restaurant. Though it wouldn't change anything even if it were vise-versa.
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Re: Efrida and Frazer who live 10 miles apart, meet at a restaur [#permalink]

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08 Jan 2013, 05:45
Bunuel,

did you apply the pythagorean theorem to the diagram above? I tried to apply it, but I get 6 and -8 as a result.

A second way that I was thinking about is the 90-60-30 degree triangular rule where the sides of the triangle are 3, 4, and 5. However, we are not certain that this triangle has this property.
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08 Jan 2013, 13:02
marcoppe wrote:
Bunuel,

did you apply the pythagorean theorem to the diagram above? I tried to apply it, but I get 6 and -8 as a result.

A second way that I was thinking about is the 90-60-30 degree triangular rule where the sides of the triangle are 3, 4, and 5. However, we are not certain that this triangle has this property.

@marcoppe most definitely bunuel used the pythagorean theorem..it is as it is because of the word DIRECTLY NORTH OR DIRECTLY EAST in the stem question signifying that we have a 90 degrees angle somewhere..well marcoppe am sorry awil ask you a dumb question but please bear with me..what does the 90-60-30 triangular rule state?and how do you apply it?

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Re: Efrida and Frazer who live 10 miles apart, meet at a restaur [#permalink]

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09 Jan 2013, 00:50
@chiccufrazer1

The 90-60-30 rule, sometimes called "Pythagorean triple" or "3-4-5 triangle", applies to those triangles that hold this property: 90°, 60°, and 30° angles. The sides of any 90-60-30 degree triangle will have its sides bearing specific length proportions: 3, 4, 5. There would be no need, therefore, to use the Pythagorean theorem in such cases.

The triangle formed in the excercise above will certainly be a 3-4-5 triangle as we have a 3-4-5 proportion in the length of its sides.
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09 Jan 2013, 01:13
marcoppe wrote:
@chiccufrazer1

The 90-60-30 rule, sometimes called "Pythagorean triple" or "3-4-5 triangle", applies to those triangles that hold this property: 90°, 60°, and 30° angles. The sides of any 90-60-30 degree triangle will have its sides bearing specific length proportions: 3, 4, 5. There would be no need, therefore, to use the Pythagorean theorem in such cases.

The triangle formed in the excercise above will certainly be a 3-4-5 triangle as we have a 3-4-5 proportion in the length of its sides.

@marcoppe. in other words what you trying to say is that we might be given a triangle that only has one side given but holds the 90-60-30 property and can still be able to find the other sides by using the pythagorean triple..if saw then how would test for the 90-60-30 property?

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09 Jan 2013, 02:14
marcoppe wrote:
Bunuel,

did you apply the pythagorean theorem to the diagram above? I tried to apply it, but I get 6 and -8 as a result.

A second way that I was thinking about is the 90-60-30 degree triangular rule where the sides of the triangle are 3, 4, and 5. However, we are not certain that this triangle has this property.

90-60-30 (angles) triangle and 3-4-5 (sides) triangle are not the same. For more check here: math-triangles-87197.html
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Re: Efrida and Frazer who live 10 miles apart, meet at a restaur [#permalink]

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09 Jan 2013, 02:38
Thanks Bunuel, I realized now that I got confused with the two principles. To know that we are dealing with a 3-4-5 right triangle there is no need to know its angles.

Sorry chiccufrazer1.

Anyways, I was curious to know how Bunuel got that result. I am pretty sure he used the pythagorean theorem, but I got -8 and 6 using Phythagora. I am not sure how to decide which one to pick.
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Re: Efrida and Frazer who live 10 miles apart, meet at a restaur [#permalink]

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09 Jan 2013, 02:54
marcoppe wrote:
Thanks Bunuel, I realized now that I got confused with the two principles. To know that we are dealing with a 3-4-5 right triangle there is no need to know its angles.

Sorry chiccufrazer1.

Anyways, I was curious to know how Bunuel got that result. I am pretty sure he used the pythagorean theorem, but I got -8 and 6 using Phythagora. I am not sure how to decide which one to pick.

Actually I didn't use Pythagorean theorem.

We know that the hypotenuse is 10 and one leg is 2 more than the other, which means that it should be 6-8-10 right triangle.

If we use the theorem then we'll have x^2+(x+2)^2=10^2 --> 2x^2+4x-96=0 --> x^2+2x-48=0 --> (x-6)(x+8)=0 --> x=6 (discard x=-8 since the distance cannot be negative).

Hope it helps.
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Re: efrida and frazer who live 10 miles apart meet at a restaur [#permalink]

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20 Nov 2013, 02:21
Bunuel wrote:
chiccufrazer1 wrote:
efrida and frazer who live 10 miles apart,meet at a restaurant that is directly north of efrida's home and directly east of frazer's home.if the restaurant is too miles closer to efrida's home,than to frazer's home,how many miles is the restaurant from frazer's home
A.6 B.7 C.8 D.10 E.11

Posted from my mobile device

Please check the questions when posting and format them properly.

Efrida and Frazer who live 10 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home?

A. 6
B. 7
C. 8
D. 10
E. 11

It's a simple geometry problem. Look at the diagram below:
Attachment:
Restraunt.PNG
From above it follows that the restaurant is 8 miles from Frazer's home and 6 miles from Efrida's home.

Solved using pure math, but took me more than 3 minutes... the draw is reaaly a shortcut.

Thanks Bunuel for this.
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