v1rok wrote:
ps_dahiya wrote:
I know B gives the answer but not sure about A.
Somehow I feel A will give the answer like 30 individual, 3 cartons of 6 and 9 cartons of 12.
So I go for D.
Exactly my feelings too! Somehow after solving numerous problems of various difficulty I am starting to get a sixth sense on these traps. I hope that my gut feeling would not let me down on the exam date...
So, anybody knows how to show that (A) is sufficient too?
A mathematical approach to solve this would be:
x = No of dozens
y = No of half-dozens
z = No of individual eggs
From the stem,
x + 0.6y+0.16z = 15 --(A)
From 2:
x = 9
z = 30
We can find y (as everyone here has found) and only one such y exists. And hence SUFF.
Condition #1.
Given
x + 0.6y+0.16z = 15 --(A)
12x+6y+z = 150 --(B)
(From #2) x = 9, y = 2 and z = 30 is defenitely one of the solutions. We are looking for alternate solution
(A)*10 - (B) gives
10x = 3z
We ALREADY KNOW that
x = 9, z = 30 --> y = 2 is a valid solution
Try to find other integer solutions for ths:
x = 3, z = 10 --> y = 104/6 Not an integer. Invalid solution
x = 6, z = 20 --> y = 58/6 Not an integer. Invalid solution
x = 12, z = 40 --> y becomes -ve. No neeto to check further
#1. is also sufficient. Hence D.
But as everyone here mentioned, all of this analysis takes a hell lot of time. It is not worth spending more than 3 minutes.
_________________
"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
- Bernard Edmonds
close
