Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 27 May 2015, 20:32

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Eight Alaskan huskies are split into pairs to pull one of

Author Message
TAGS:
Senior Manager
Joined: 05 Mar 2006
Posts: 348
Followers: 1

Kudos [?]: 8 [0], given: 0

Eight Alaskan huskies are split into pairs to pull one of [#permalink]  12 Aug 2006, 13:10
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Eight Alaskan huskies are split into pairs to pull one of four sleds in a race. How many different assignments of Huskies to sleds are possible?

32

64

420

1680

2520
Manager
Joined: 23 Jul 2006
Posts: 50
Followers: 1

Kudos [?]: 1 [0], given: 0

HI...

I think is E.

For the first pair of dogs we have: 8C2
For the second pair : 6C2
For the third pair: 4C2
Finally, for the last pair: 2C2

THen, the total number is: 8C2 x 6C2 x 4C2 x 2C2 = 2520

is it OK?
_________________

Woody crack the GMAT

Manager
Joined: 20 Mar 2006
Posts: 200
Followers: 1

Kudos [?]: 1 [0], given: 0

Re: Hard Perm/Comb PS #1 [#permalink]  13 Aug 2006, 14:46
agsfaltex wrote:
Eight Alaskan huskies are split into pairs to pull one of four sleds in a race. How many different assignments of Huskies to sleds are possible?

32

64

420

1680

2520

# of ways = 8c2 * 6c2 * 4c2* 1
=2520

Hence E

Heman
SVP
Joined: 30 Mar 2006
Posts: 1738
Followers: 1

Kudos [?]: 46 [0], given: 0

E.

For the first sled two huskies can be chosen in 8C2 = 28 ways
For the second sled two huskies can be chosen in 6C2 = 15 ways
For the third sled two huskies can be chosen in 4C2 = 6 ways
For the fourth sled two huskies can be chosen in 2C2 = 1 way

Total = 28*15*6 = 2520
Manager
Joined: 26 Jun 2006
Posts: 152
Followers: 1

Kudos [?]: 1 [0], given: 0

I got to 2520 part, but then I multiplied it by 4!=24, because I thought that Pair#1 can be assigned to one of the four sleds, Pair#2 can be assigned to one of remaining three, and so on...

I guess I overanalyzed it a little bit
Similar topics Replies Last post
Similar
Topics:
Ten Arabian horses are split into pairs to pull one of the distinct 0 12 Sep 2014, 10:33
14 Three pairs of siblings, each pair consisting of one girl 9 05 Aug 2012, 03:32
2 10 Arabian horses are split into pairs to pull one of the 5 06 Jun 2010, 07:57
17 Nine dogs are split into 3 groups to pull one of three 10 03 Jan 2010, 05:03
An eight-card deck consists of 4 pairs of each suit. 2 cards 3 03 Sep 2006, 10:03
Display posts from previous: Sort by