Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Also Killer u missed out the possibilities of 0, 8 and 8,0. Moreover u missed out the possibilites of 8 people being divided into more than 2 groups.

1. The stem clearly state "Eight people are to be divided into two groups. What is the probability that there will be 4 in each groups?"

2. For me 0,8 means that you don't have two groups only one group of eight people. I don't like philosophical questions. (i.e. "what is a group of people ?").

Also Killer u missed out the possibilities of 0, 8 and 8,0. Moreover u missed out the possibilites of 8 people being divided into more than 2 groups.

1. The stem clearly state "Eight people are to be divided into two groups. What is the probability that there will be 4 in each groups?"

2. For me 0,8 means that you don't have two groups only one group of eight people. I don't like philosophical questions. (i.e. "what is a group of people ?").

3. what's the OA.

Sorry for the confusion. I think I explained it the wrong way.

THere is my actual expanation.

Dividing people into 2 groups of 4 requires choosing 4 people from 8. So 8C4 is the number of the ways of forming 2 groups of 4. So far so good.

Now for the total number of ways of forming 2 groups. This can be as you said groups of 1,7, and 7,1 2,6 and 6,2 3,5 and 5,3 4,4 and the philosophical 0,8 and 8,0. Now I feel we need to calculate the number of ways we can get these combinations. So for 1,7 it is 8C1*8C7. Similarly for 2,6 it is 8C2*8C6, for 5,3 it is 8C3*8C5, for 8,0 it is 8C0*8C8 and for 4,4 it is 8C4*8C4

Now on adding these we get (8C1)^2 + (8C2)^2 + (8C3)^2 + (8C4)^2 and the philosophical (8C0)^2

I guess the answer wud be 8C4/((8C1)^2 + (8C2)^2 + (8C3)^2 + (8C4)^2 and the philosophical (8C0)^2)

Now to take it one step further if the order of the groups matters then it is

8C4/2*((8C1)^2 + (8C2)^2 + (8C3)^2 + (8C4)^2 and the philosophical (8C0)^2)

Also Killer u missed out the possibilities of 0, 8 and 8,0. Moreover u missed out the possibilites of 8 people being divided into more than 2 groups.

1. The stem clearly state "Eight people are to be divided into two groups. What is the probability that there will be 4 in each groups?"

2. For me 0,8 means that you don't have two groups only one group of eight people. I don't like philosophical questions. (i.e. "what is a group of people ?").

3. what's the OA.

Sorry for the confusion. I think I explained it the wrong way.

THere is my actual expanation.

Dividing people into 2 groups of 4 requires choosing 4 people from 8. So 8C4 is the number of the ways of forming 2 groups of 4. So far so good.

Now for the total number of ways of forming 2 groups. This can be as you said groups of 1,7, and 7,1 2,6 and 6,2 3,5 and 5,3 4,4 and the philosophical 0,8 and 8,0. Now I feel we need to calculate the number of ways we can get these combinations. So for 1,7 it is 8C1*8C7. Similarly for 2,6 it is 8C2*8C6, for 5,3 it is 8C3*8C5, for 8,0 it is 8C0*8C8 and for 4,4 it is 8C4*8C4

Now on adding these we get (8C1)^2 + (8C2)^2 + (8C3)^2 + (8C4)^2 and the philosophical (8C0)^2

I guess the answer wud be 8C4/((8C1)^2 + (8C2)^2 + (8C3)^2 + (8C4)^2 and the philosophical (8C0)^2)

Now to take it one step further if the order of the groups matters then it is

8C4/2*((8C1)^2 + (8C2)^2 + (8C3)^2 + (8C4)^2 and the philosophical (8C0)^2)

Hello dahcrap - I like your thinking but I recommend that you will use the "occam's razor" on this one - don't forget you have only two minutes !!!

Also Killer u missed out the possibilities of 0, 8 and 8,0. Moreover u missed out the possibilites of 8 people being divided into more than 2 groups.

1. The stem clearly state "Eight people are to be divided into two groups. What is the probability that there will be 4 in each groups?"

2. For me 0,8 means that you don't have two groups only one group of eight people. I don't like philosophical questions. (i.e. "what is a group of people ?").

3. what's the OA.

Sorry for the confusion. I think I explained it the wrong way.

THere is my actual expanation.

Dividing people into 2 groups of 4 requires choosing 4 people from 8. So 8C4 is the number of the ways of forming 2 groups of 4. So far so good.

Now for the total number of ways of forming 2 groups. This can be as you said groups of 1,7, and 7,1 2,6 and 6,2 3,5 and 5,3 4,4 and the philosophical 0,8 and 8,0. Now I feel we need to calculate the number of ways we can get these combinations. So for 1,7 it is 8C1*8C7. Similarly for 2,6 it is 8C2*8C6, for 5,3 it is 8C3*8C5, for 8,0 it is 8C0*8C8 and for 4,4 it is 8C4*8C4

Now on adding these we get (8C1)^2 + (8C2)^2 + (8C3)^2 + (8C4)^2 and the philosophical (8C0)^2

I guess the answer wud be 8C4/((8C1)^2 + (8C2)^2 + (8C3)^2 + (8C4)^2 and the philosophical (8C0)^2)

Now to take it one step further if the order of the groups matters then it is

8C4/2*((8C1)^2 + (8C2)^2 + (8C3)^2 + (8C4)^2 and the philosophical (8C0)^2)

Hello dahcrap - I like your thinking but I recommend that you will use the "occam's razor" on this one - don't forget you have only two minutes !!!