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Employees of a department store receive a 20% discount on

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Employees of a department store receive a 20% discount on [#permalink] New post 25 Aug 2006, 06:43
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A
B
C
D
E

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Employees of a department store receive a 20% discount on the discounted price of all store merchandise. As the holiday season is coming to an end, some of the socks in the menswear department have been marked down by 40%, and the rest have been marked down by only 10%. Sean, a department store employee bought 16 pairs of socks whose original price was $10.00 each. Were most of the pairs marked down by 40%?

(1) He paid for the socks with a $100 bill.
(2) If Sean were not a department store employee, he would have paid less than $120.

Last edited by kevincan on 25 Aug 2006, 07:38, edited 1 time in total.
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 [#permalink] New post 25 Aug 2006, 07:14
IMO if he bought 8 pairs with 40% discount and 8 pairs with 10% discount , this would cost Shean 120$ for the 16 pairs.
A is sufficient to ans the question and so is B
D should be the ans
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 [#permalink] New post 25 Aug 2006, 08:54
D it is ...

From 1, total without discount >= $125

Hence we get x + y = 16 and 9x+6y >= 125
SUFF

From 2, total < 120, hence x = y =16 and 9x+6y <= 120
SUFF

Hence answer is D
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 [#permalink] New post 25 Aug 2006, 10:47
gmatornot wrote:
D it is ...

From 1, total without discount >= $125

Hence we get x + y = 16 and 9x+6y >= 125
SUFF

From 2, total < 120, hence x = y =16 and 9x+6y <= 120
SUFF

Hence answer is D


can u pls explain in more detail pls ?
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 [#permalink] New post 25 Aug 2006, 11:05
I am getting strange results with this problem. pls tell me where I am going wrong.

let m pairs be discounted 40%, and n pairs be discounted 10%
For each pair,
Original price = 10
Discounted price = 6 and 9 resp
Dicounted price for emps = 0.8 * discounted price
= 4.8 and 7.2 resp.

from st (1):
100 = 4.8m + 7.2n and m + n = 16
Solving for n, I get n = 29/3 = 10 (since m and n have to be integers)
hence, m = 6

from st (2):
6m + 9n < 120 and m + n = 16
Again solving for n, I get n < 8. Hence m >= 8.

I am wondering, are these 2 statements talking abt the same thing ? (since I am getting 2 completely diff ans for m from 1 and 2
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 [#permalink] New post 25 Aug 2006, 11:16
prashrash wrote:
I am getting strange results with this problem. pls tell me where I am going wrong.

let m pairs be discounted 40%, and n pairs be discounted 10%
For each pair,
Original price = 10
Discounted price = 6 and 9 resp
Dicounted price for emps = 0.8 * discounted price
= 4.8 and 7.2 resp.

from st (1):
100 = 4.8m + 7.2n and m + n = 16
Solving for n, I get n = 29/3 = 10 (since m and n have to be integers)
hence, m = 6

from st (2):
6m + 9n < 120 and m + n = 16
Again solving for n, I get n < 8. Hence m >= 8.

I am wondering, are these 2 statements talking abt the same thing ? (since I am getting 2 completely diff ans for m from 1 and 2


In (1), where do you get that the socks cost $100?
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 [#permalink] New post 25 Aug 2006, 11:52
kevincan wrote:
In (1), where do you get that the socks cost $100?


(1) He paid for the socks with a $100 bill.

oops realized my mistake .. from st (1), we should get
100 >= 4.8m + 7.2n ( we don't know if change was given or not)
solving we get, n <= 10
so, m >= 6

so after applying the correction, (1) and (2) is still INSUFF .. hence (E) ??
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 [#permalink] New post 25 Aug 2006, 11:58
prashrash wrote:
I am getting strange results with this problem. pls tell me where I am going wrong.

let m pairs be discounted 40%, and n pairs be discounted 10%
For each pair,
Original price = 10
Discounted price = 6 and 9 resp
Dicounted price for emps = 0.8 * discounted price
= 4.8 and 7.2 resp.

from st (1):
100 = 4.8m + 7.2n and m + n = 16
Solving for n, I get n = 29/3 = 10 (since m and n have to be integers)
hence, m = 6

from st (2):
6m + 9n < 120 and m + n = 16
Again solving for n, I get n < 8. Hence m >= 8.
I am wondering, are these 2 statements talking abt the same thing ? (since I am getting 2 completely diff ans for m from 1 and 2


I don't understand the greater than or equal to sign here.
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 [#permalink] New post 25 Aug 2006, 12:26
this is D..just use simple logic
if the total bill wihtout discout is $160...and if all the socks were 10% off it would $146...

then 20% employee discount would be roughly $120 dollar...

so...we can see definetly if he paid $100...then most of the socks bought were 40% (i.e greater than 8)

1) is sufficient
2) is sufficient
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 [#permalink] New post 25 Aug 2006, 12:36
kevincan wrote:
prashrash wrote:
I am getting strange results with this problem. pls tell me where I am going wrong.

let m pairs be discounted 40%, and n pairs be discounted 10%
For each pair,
Original price = 10
Discounted price = 6 and 9 resp
Dicounted price for emps = 0.8 * discounted price
= 4.8 and 7.2 resp.

from st (1):
100 = 4.8m + 7.2n and m + n = 16
Solving for n, I get n = 29/3 = 10 (since m and n have to be integers)
hence, m = 6

from st (2):
6m + 9n < 120 and m + n = 16
Again solving for n, I get n < 8. Hence m >= 8.
I am wondering, are these 2 statements talking abt the same thing ? (since I am getting 2 completely diff ans for m from 1 and 2


I don't understand the greater than or equal to sign here.


oh no! another mistake.
solved for n and got n < 8. since m + n = 16, I took m >= 8.
but if m = 8, then n = 8 and 6m + 9n will be = 120.
thus m cannot be = 8.
so m > 8 and n < 8.
thus (B) is the answer.
thanx for the correction kevincan.
i am losing out due to such oversights all the time :oops:
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Prashrash.

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 [#permalink] New post 25 Aug 2006, 12:39
Thank YOU for trying the question!

OA=B
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 [#permalink] New post 25 Aug 2006, 15:06
It will be B

Statement 1 - with 8 sock sat 40% discount and 8 socks with 10% discount, it would cost Sean $96.00. So when he pays with $100 it is not sure if he bought more 10% discount socks or 40% discount socks. So

Statement 2 - will tell that if he paid less than 120 dollars then he bought 40% socks more...
  [#permalink] 25 Aug 2006, 15:06
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