ncprasad wrote:

Swagatalakshmi wrote:

Solve :

| |Câ€“1|+|C| | = |C+3|â€“C

Let C<0, then the equation becomes

||-(c-1)+-c|=-(c+3)-c

|-2c+1|=2c-3

2c-1=-2c-3

4c=-2

c=-1/2

Let C>0, using |a+b|=|a|+|b|, the equation becomes

||c-1||+||c||+c=|c+3|

c-1+c+c=c+3

c=2

Solutions for C are 2,-1/2.

I plugged these values into the original equation and they satisfy.

Sorry... but ||-1/2-1| + |-1/2|| = |1,5 + 0,5| = 2 and |-1/2 + 3| - (-1/2) = 2,5 + 0,5 = 3. Thus, the solution -1/2 is not correct.