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Equation |x/2| + |y/2| = 5 encloses a certain region on the

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Director
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New post 23 May 2007, 23:10
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Equation |x/2| + |y/2| = 5 encloses a certain region on the co-ord plane. What is the area of this region?

Source: http://www.gmatclub.com/phpbb/viewtopic.php?t=19483


My sol:

x = (10, -10)
y = (10, -10)


so the area = 20 x 20 = 400.

this is the max area.
SVP
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New post 23 May 2007, 23:28
The area is rather 200 than 400 :)

The vertice of the square are:
> A(10,0)
> B(0,10)
> C(-10,0)
> D(0,-10)

So for one side AB, we have:
AB^2 = 10^2 + 10^2 = 200


Finally, the area is : AB^2 = 200
Director
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New post 23 May 2007, 23:42
Fig wrote:
The area is rather 200 than 400 :)

The vertice of the square are:
> A(10,0)
> B(0,10)
> C(-10,0)
> D(0,-10)

So for one side AB, we have:
AB^2 = 10^2 + 10^2 = 200


Finally, the area is : AB^2 = 200


right, right. gotta. :beat
Manager
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New post 24 May 2007, 00:00
nice que.
following will be the 4 equations
y=-x+10
y= x+10
y=-x-10
y= x-10

these 4 lines will intersect each other to make a square of 10sqrt(2) side.

so area 10sqrt(2) * 10sqrt(2) =200
  [#permalink] 24 May 2007, 00:00
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