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Euqation of Line X is: 23x + 50y = 123. Which of the

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Euqation of Line X is: 23x + 50y = 123. Which of the [#permalink] New post 16 Oct 2003, 02:46
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Euqation of Line X is: 23x + 50y = 123.
Which of the following lines is perpendicular to line X:

A) 23x - 50y - 123=0
B) 50x + 23y +123=0
C) 50x -23y + 123=0
D) 100x -23y - 123=0
E) 100x +23y - 123=0
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Re: PS: perpendicular lines [#permalink] New post 16 Oct 2003, 03:01
Vicky wrote:
Euqation of Line X is: 23x + 50y = 123.
Which of the following lines is perpendicular to line X:

A) 23x - 50y - 123=0
B) 50x + 23y +123=0
C) 50x -23y + 123=0
D) 100x -23y - 123=0
E) 100x +23y - 123=0


C

slope of line X = -23/50

slope of required line = 50/23
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 [#permalink] New post 17 Oct 2003, 07:04
thats correct.
Slopes of pependicular lines are negative reciprocals of each other.
i.e. if m & n are slopes of two lines perpendicular to each other
then m*n = -1
  [#permalink] 17 Oct 2003, 07:04
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