Euqation of Line X is: 23x + 50y = 123. Which of the : PS Archive
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# Euqation of Line X is: 23x + 50y = 123. Which of the

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Euqation of Line X is: 23x + 50y = 123. Which of the [#permalink]

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16 Oct 2003, 01:46
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Euqation of Line X is: 23x + 50y = 123.
Which of the following lines is perpendicular to line X:

A) 23x - 50y - 123=0
B) 50x + 23y +123=0
C) 50x -23y + 123=0
D) 100x -23y - 123=0
E) 100x +23y - 123=0
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16 Oct 2003, 02:01
Vicky wrote:
Euqation of Line X is: 23x + 50y = 123.
Which of the following lines is perpendicular to line X:

A) 23x - 50y - 123=0
B) 50x + 23y +123=0
C) 50x -23y + 123=0
D) 100x -23y - 123=0
E) 100x +23y - 123=0

C

slope of line X = -23/50

slope of required line = 50/23
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17 Oct 2003, 06:04
thats correct.
Slopes of pependicular lines are negative reciprocals of each other.
i.e. if m & n are slopes of two lines perpendicular to each other
then m*n = -1
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