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evensflow: What big stuff is there to do In India? JP:

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Eternal Intern
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evensflow: What big stuff is there to do In India? JP: [#permalink] New post 12 Jul 2003, 14:58
:lol:

evensflow: What big stuff is there to do In India?
JP: Detroit?

Stoylar: Moscow

Triangle ABC and ABD share side AB. Triangle ABC has area Q and Triangle ABD has area R. If AD is longer than AC and BD is longer than BC, which of the following could be true?

I) R > Q

II) R= Q
III) R < Q




Triangle ABC and ABD share side AB. Triangle ABC has area Q and Triangle ABD has area R. If AD is longer than AC and BD is longer than BC, which of the following could be true?

I) R > Q

II) R= Q
III) R < Q

I have tried every drawing of the sides and stuff but it hasn't worked out yet.


All three can be true. In the diagrams, the red lines are parallel to AB which is drawn as the base for both triangles. The red lines are also equidistant from AB. Since area = (1/2) base * height and the bases are the same for each triangle, we only need to compare the heights. The height is the perpendicular distance of the third point of each triangle to the line passing through AB.


R > Q





since D is past the red line, R > Q




R = Q





since D is on the red line, R = Q




R < Q





since D is behind the red line, R < Q




in all three diagrams AD > AC and BD > BC

Last edited by Curly05 on 16 Jul 2003, 17:28, edited 1 time in total.
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Nope all three [#permalink] New post 13 Jul 2003, 05:13
That is what makes this question so hard, all three is right, according to ETS!

Anyone else can help out would be greatly appreciated. Why do you say two is right?
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 [#permalink] New post 13 Jul 2003, 05:19
I is clear. There are many examples

II The triangles sharing the same base can have the same heights. Thus, their areas are equal.

III (???)
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Stolyar [#permalink] New post 13 Jul 2003, 06:04
Somehow, I think ETS wants you to draw a special sort of triangle.

Rule Out Isosceles, and Equilateral.

Does the height of the triangle reach the vertex or the top ?

And the height of the triangle is determined by the left and right sides, so the longer the sides, the further the height reaches ? :?:


There's no way two and three can be right, but they are.

The answer key is not lying!
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 [#permalink] New post 13 Jul 2003, 17:11
Yes! All three are possible.

ETS is so good in formating questions those are nothing to do
with math skills, but to do with crative thinking.

Assume, ABD triangle with two angles equal 1 degree and other is 178.
But ABC with all the three angles as 60 degrees.

That will satisfy the third condition.
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Kpadama [#permalink] New post 13 Jul 2003, 17:39
Hey I need someone to draw a diagram to see all three, it is impossible for us to learn without one. Which angle is 178, it can't be ADB.
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All three is possible. [#permalink] New post 14 Jul 2003, 11:35
I draw a picture, hope you can see it clearly.
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 [#permalink] New post 14 Jul 2003, 21:12
It is just a game "common base and height"
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 [#permalink] New post 15 Jul 2003, 02:55
OKies here's my answer,

What i know of an area of triangle is that it is 1/2 * base * side length * Sine of the included angle between them.

So depending upon your sine value of the angle the are can be less than, equal to or greater than the other area.

HTH:)

P.S: Well, Curly, somehow i just fail to understand your questions. You either seem to be interested in other topics apart from the question or you provide half information abt the question. I would appreciate your questions if you could please seperate your personal questions from the main GMAT questions which you wish to get answered. You talk about a GMAT question one moment and the next you want to know wassup in Moscow or in India.

This is a good will gesture, i dont mean to hurt anyone. But please try to maintain the personal questions at the end of the post rather than at the begining and stick to the question wherein everyone will benefit. :)
  [#permalink] 15 Jul 2003, 02:55
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