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EXPONENTIALS Q

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EXPONENTIALS Q [#permalink] New post 06 Jan 2004, 18:40
Any idea :shock: Pls include reasoning along with all answer posts.

The value of (2^3/4 + 2^1/2 + 2^1/4 + 1)(2^1/4 - 1)

a. 5
2. 7
3. -1
4. 1
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 [#permalink] New post 06 Jan 2004, 18:52
4)

= 2^(3/4+1/4) + [-1][2^3/4] + 2^(1/2+1/4) + [-1][2^1/2] + 2^(1/4+1/4) + [-1][2^1/4] + 2^1/4 - 1
= 2 - 2^3/4 + 2^3/4 - 2^1/2 + 2^1/2 - 2^1/4 + 2^1/4 -1
= 2 - 1
= 1
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 [#permalink] New post 06 Jan 2004, 18:54
[quote="Paul"]4)

= 2^(3/4+1/4) + [-1][2^3/4] + 2^(1/2+1/4) + [-1][2^1/2] + 2^(1/4+1/4) + [-1][2^1/4] + 2^1/4 - 1
= 2 - 2^3/4 + 2^3/4 - 2^1/2 + 2^1/2 - 2^1/4 + 2^1/4 -1
= 2 - 1
= 1[/quote]



How many minutes did that take you approx?
Is there a short cut?
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Pls include reasoning along with all answer posts.
****GMAT Loco****
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 [#permalink] New post 06 Jan 2004, 18:57
the time writing took me much longer than doing it. 30 sec to do it
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 [#permalink] New post 06 Jan 2004, 18:58
I'm thoroughly confused by this problem for some reason.
What exponential rules did your use?
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 [#permalink] New post 06 Jan 2004, 19:00
Just know the rule to multiply and add exponents. When same base is multiplied, in this case 2, you can just add up their exponents
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 [#permalink] New post 06 Jan 2004, 19:06
I made daft mistake.
Cheers
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  [#permalink] 06 Jan 2004, 19:06
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EXPONENTIALS Q

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