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Re: Exponents [#permalink]
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gxsingh wrote:
I personally prefer the way silvers solved it!

Agreed! Prime factoring is the way to go!



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Re: Exponents [#permalink]
flash2374 wrote:
\(\frac{(8^2)(3^2)(2^4)}{96^2} =\)

Can you please solve? What level question is this?


I guess this must be around 600-650 types level question not sure though .. !

Anyway you can break down this expression to make it simple

\(\frac{(8^2)(3^2)(2^4)}{96^2} = \frac{(8^ 2) (3^2) (2^4)}{(16 * 6 *16 * 6)}\)

And then u can easily solve this one ..!
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Re: Exponents [#permalink]
\(\frac{(8^2)(3^3)(2^4)}{96^2} =\)

I'm sorry, I originally mistyped 3^2 instead of 3^3. Can you please solve it again? The answer should come to 3.
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Re: Exponents [#permalink]
Thanks. I see it now.
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Re: Exponents [#permalink]
nitishmahajan wrote:
flash2374 wrote:
\(\frac{(8^2)(3^2)(2^4)}{96^2} =\)

Can you please solve? What level question is this?


I guess this must be around 600-650 types level question not sure though .. !

Anyway you can break down this expression to make it simple

\(\frac{(8^2)(3^2)(2^4)}{96^2} = \frac{(8^ 2) (3^2) (2^4)}{(16 * 6 *16 * 6)}\)

And then u can easily solve this one ..!


I solved the answer with Silver's explanation. I'm just curious to understand your reasoning. I see that 16 * 6 is 96 so 96^2 would be 16 * 6 * 16 * 6. Then you can cancel out 2^4 and one of the 16s. You are left with (8^2)(3^3)/(16*6*6). Then you can make it (4 * 27) / 36. Then (4 * 3) / 4 = 3.
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Re: Exponents [#permalink]
flash2374 wrote:
nitishmahajan wrote:
flash2374 wrote:
\(\frac{(8^2)(3^2)(2^4)}{96^2} =\)

Can you please solve? What level question is this?


I guess this must be around 600-650 types level question not sure though .. !

Anyway you can break down this expression to make it simple

\(\frac{(8^2)(3^2)(2^4)}{96^2} = \frac{(8^ 2) (3^2) (2^4)}{(16 * 6 *16 * 6)}\)

And then u can easily solve this one ..!


I solved the answer with Silver's explanation. I'm just curious to understand your reasoning. I see that 16 * 6 is 96 so 96^2 would be 16 * 6 * 16 * 6. Then you can cancel out 2^4 and one of the 16s. You are left with (8^2)(3^3)/(16*6*6). Then you can make it (4 * 27) / 36. Then (4 * 3) / 4 = 3.


you can actually solve this with many ways, generally I try to cancel the big numbers, so that the calculation becomes easier later on .. and it also decreases the number steps involved for me ... Anyway, one should follow the method with which they are comfortable with ..!
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Re: Exponents [#permalink]
I personally prefer the way silvers solved it!
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Re: Exponents [#permalink]
flash2374 wrote:
nitishmahajan wrote:
flash2374 wrote:
\(\frac{(8^2)(3^2)(2^4)}{96^2} =\)

Can you please solve? What level question is this?


I guess this must be around 600-650 types level question not sure though .. !

Anyway you can break down this expression to make it simple

\(\frac{(8^2)(3^2)(2^4)}{96^2} = \frac{(8^ 2) (3^2) (2^4)}{(16 * 6 *16 * 6)}\)

And then u can easily solve this one ..!


I solved the answer with Silver's explanation. I'm just curious to understand your reasoning. I see that 16 * 6 is 96 so 96^2 would be 16 * 6 * 16 * 6. Then you can cancel out 2^4 and one of the 16s. You are left with (8^2)(3^3)/(16*6*6). Then you can make it (4 * 27) / 36. Then (4 * 3) / 4 = 3.


Choose the method that suits u the best and will give u the most confident(hopefully the right) answer in the shortest period of time :-D
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