Exponents & Roots: Data Sufficiency : Quant Question Archive [LOCKED]
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# Exponents & Roots: Data Sufficiency

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Exponents & Roots: Data Sufficiency [#permalink]

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29 Jan 2007, 21:18
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How would you solve?

8^a(1/4)^b=?

(1) b = 1.5a
(2) a = 2
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Re: Exponents & Roots: Data Sufficiency [#permalink]

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29 Jan 2007, 22:02
above720 wrote:
How would you solve?

8^a(1/4)^b=?

(1) b = 1.5a
(2) a = 2

I am not sure how to read the question is it
8^a*(1/4)^b=
or
8^(a*(1/4)^b)=

try to solve the first one

8^a*(1/4)^b=
{(1/2)^-3a}*{(1/2)^-2b)}
(1)statement b = 1.5a substitute in original equation
{(1/2)^-3a}*{(1/2)^(-2*1.5a)}=
{(1/2)^-3a}*{(1/2)^(-3a)}=8^2a
2)is clearly insuff
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Re: Exponents & Roots: Data Sufficiency [#permalink]

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30 Jan 2007, 04:34
above720 wrote:
How would you solve?

8^a(1/4)^b=?

(1) b = 1.5a
(2) a = 2

if the question is

8^a * (1/4)^b

= 2^3a * (1/2)^ 2b

(1) b = 1.5a

then 2^3a * (1/2)^ 2b = 2^3a * (1/2) ^ 3a =1

Ans = A

if the question is 8^[a(1/4)]^b
then Ans= C
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30 Jan 2007, 06:21
How would you solve?

8^a(1/4)^b=?

(1) b = 1.5a
(2) a = 2

8^a(1/4)^b= = 2^3a * 2^-2b = 2^3a -2 b

from one

THE EXPRESSION IS DOWN TO 2^0 = 1......SUFF

from two

no info about value of b.......not suff

ANSWER IS INDEED A , THANKS SUMITHRA

Last edited by yezz on 30 Jan 2007, 06:31, edited 1 time in total.
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30 Jan 2007, 06:30
SUMITHRA , THANKS MAN U R RIGHT

I FORGOT THE CRAZY 2

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30 Jan 2007, 06:31
8^a(1/4)^b=?

(1) b = 1.5a
(2) a = 2

(8^a)(1/4)^b
Subsitute b from 1

(8)^a(1/4)^1.5a

This an example of (a)^x (b)^x. Cannot be solved. Hence B, C, E

From 2 it is not possible to find a value of the equation. Hence C, E
Combining 1 and 2

You can easily find the value of the equation. Hence C is the best answer
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30 Jan 2007, 07:53
yezz wrote:
SUMITHRA , THANKS MAN U R RIGHT

I FORGOT THE CRAZY 2

You are welcome.

Guess, you just need to relax before the big day.

You'll do fine. All the best.
30 Jan 2007, 07:53
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