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# F(12) = 2*4*6*8*10*12 what is the largest prime factor of

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Manager
Joined: 11 Jul 2004
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F(12) = 2*4*6*8*10*12 what is the largest prime factor of [#permalink]  31 Aug 2004, 10:08
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F(12) = 2*4*6*8*10*12

what is the largest prime factor of f(24)

thanks
Intern
Joined: 10 Aug 2004
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My guess is 11. The factorial of f(24) leaves us with 2^22*3^5*5^2*7^1*11^1. Being that a prime number has only two factors (1 and itself), the largest prime factor is 11.
Manager
Joined: 02 Apr 2004
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Location: Utrecht
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I used the same approach like abennett and got also 11 as the largest prime of F(24).

By factoring them all out it is possible to reach 11 as the largest prime since an prime is only divisibly by one and itself.

Correct me if I am wrong.

Regards,

Alex
Joined: 31 Dec 1969
Location: India
Concentration: General Management, Strategy
GMAT 1: 710 Q49 V0
GMAT 2: 740 Q40 V50
GMAT 3: 700 Q48 V38
GPA: 3.6
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Kudos [?]: 88 [0], given: 86987

Does F refer to factorial ? I'm not sure it means factorial because in the question, because it says F(12) = 2*4*6*8*10*12.
If F is factorial then F(12) = 12*11*9*8*7*6*5*4*4*2*1
Intern
Joined: 30 Aug 2004
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No 'guest'...F does nt refer to factorial.....is is the product of the even integers less than or equal to the n in F(n)

thus F(24)=2.4.6.8.10.12.14.16.18.20.22.24

factorize.....u get 2.(2^2).(2.3).(2^3).(2.5).(2^2 *3)............n thus the pwers mentioned in the earlier post wid highes prim factor 11.........the answer......

i hp i m not wrong
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