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# f(x) is defined as the largest integer N such that X is

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f(x) is defined as the largest integer N such that X is [#permalink]  22 Oct 2007, 12:32
f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?

f(24)
f(42)
f(62)
f(76)
f(84)
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Re: Challenge - Functions [#permalink]  22 Oct 2007, 13:12
I guess its f(84). Since 2^84 gives the largets divisor. Hence the number divisible by 2^84 will be the greatest. Moreover as all are powers of 2 all others 1-4 options also divide the number N = 2^84.
Any other answers. Pls correct me

Darshan

bmwhype2 wrote:
f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?

f(24)
f(42)
f(62)
f(76)
f(84)
VP
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Posts: 1469
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Kudos [?]: 84 [1] , given: 0

Re: Challenge - Functions [#permalink]  22 Oct 2007, 13:18
1
KUDOS
bmwhype2 wrote:
f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?

f(24)
f(42)
f(62)
f(76)
f(84)

f(x) = n
where x/2^n is an integer
24 = 2*2*2*3, n=3
42 = 2*21, n=1
62 = 2*31, n=1
76 = 2*2*19, n=2
84 = 2*2*21, n=2
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Re: Challenge - Functions [#permalink]  22 Oct 2007, 13:46
Oh I got the q wrong thx

bkk145 wrote:
bmwhype2 wrote:
f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?

f(24)
f(42)
f(62)
f(76)
f(84)

f(x) = n
where x/2^n is an integer
24 = 2*2*2*3, n=3
42 = 2*21, n=1
62 = 2*31, n=1
76 = 2*2*19, n=2
84 = 2*2*21, n=2
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bkk145,

Andy Huang
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A.Haung wrote:
bkk145,

Andy Huang

My 1000 posts!!! yeah!

Actually, I assumed that "N" is the same as "n". I don't know if it is a typo or what, but without that assumption, I wouldn't be able to connect the dots. I hope my answer is right.

I don't think I have any particular way to attack the question. I just wrote out the logic. One thing to remember is that function itself has no relation with its output. Often, a function problem will use the input value (in this case x) and try to confuse you into thinking that it has something to do with the output (in this case n). In this problem, if the x and 2^n condition is not given, just remember that x and n has no logical relation with each other. Maybe that will help you see clearer. Hope this helps.
CEO
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Posts: 2774
Location: New York City
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Kudos [?]: 169 [0], given: 4

bkk145 wrote:
A.Haung wrote:
bkk145,

Andy Huang

My 1000 posts!!! yeah!

Actually, I assumed that "N" is the same as "n". I don't know if it is a typo or what, but without that assumption, I wouldn't be able to connect the dots. I hope my answer is right.

I don't think I have any particular way to attack the question. I just wrote out the logic. One thing to remember is that function itself has no relation with its output. Often, a function problem will use the input value (in this case x) and try to confuse you into thinking that it has something to do with the output (in this case n). In this problem, if the x and 2^n condition is not given, just remember that x and n has no logical relation with each other. Maybe that will help you see clearer. Hope this helps.

N is the same as n. Sorry, should've been more meticulous

OA is A
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Re: Challenge - Functions [#permalink]  06 Dec 2007, 09:24
f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?

f(24)
f(42)
f(62)
f(76)
f(84))
In my opinion A is the answer. A gives us that f(24). Thus, we have f(24)=24/2^n. 24 is 2^3 *3, therefore n could be 3. in B and C n would be 1, while in D n would be 2.
Re: Challenge - Functions   [#permalink] 06 Dec 2007, 09:24
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