|
Author |
Message |
|
TAGS:
|
|
|
CEO
Joined: 21 Jan 2007
Posts: 2797
Location: New York City
Followers: 5
Kudos [?]:
132
[0], given: 4
|
f(x) is defined as the largest integer N such that X is [#permalink]
 22 Oct 2007, 13:32
f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?
f(24)
f(42)
f(62)
f(76)
f(84)
|
|
|
|
|
|
|
Intern
Joined: 16 Oct 2007
Posts: 23
Followers: 0
Kudos [?]:
0
[0], given: 0
|
Re: Challenge - Functions [#permalink]
22 Oct 2007, 14:12
I guess its f(84). Since 2^84 gives the largets divisor. Hence the number divisible by 2^84 will be the greatest. Moreover as all are powers of 2 all others 1-4 options also divide the number N = 2^84.
Any other answers. Pls correct me
Darshan
bmwhype2 wrote: f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?
f(24)
f(42)
f(62)
f(76)
f(84)
|
|
|
|
|
|
VP
Joined: 10 Jun 2007
Posts: 1478
Followers: 5
Kudos [?]:
70
[0], given: 0
|
Re: Challenge - Functions [#permalink]
22 Oct 2007, 14:18
bmwhype2 wrote: f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?
f(24)
f(42)
f(62)
f(76)
f(84)
f(24) is the answer
f(x) = n
where x/2^n is an integer
24 = 2*2*2*3, n=3
42 = 2*21, n=1
62 = 2*31, n=1
76 = 2*2*19, n=2
84 = 2*2*21, n=2
|
|
|
|
|
|
Intern
Joined: 16 Oct 2007
Posts: 23
Followers: 0
Kudos [?]:
0
[0], given: 0
|
Re: Challenge - Functions [#permalink]
22 Oct 2007, 14:46
Oh I got the q wrong thx
bkk145 wrote: bmwhype2 wrote: f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?
f(24)
f(42)
f(62)
f(76)
f(84) f(24) is the answer f(x) = n where x/2^n is an integer 24 = 2*2*2*3, n=3 42 = 2*21, n=1 62 = 2*31, n=1 76 = 2*2*19, n=2 84 = 2*2*21, n=2 |
|
|
|
|
|
Manager
Joined: 07 Sep 2007
Posts: 80
Followers: 1
Kudos [?]:
4
[0], given: 0
|
bkk145,
i only understand what the question was asking after reading your answer. Can you tell me how you attack the question?
Andy Huang
|
|
|
|
|
|
VP
Joined: 10 Jun 2007
Posts: 1478
Followers: 5
Kudos [?]:
70
[0], given: 0
|
A.Haung wrote: bkk145,
i only understand what the question was asking after reading your answer. Can you tell me how you attack the question?
Andy Huang
My 1000 posts!!! yeah!
Actually, I assumed that "N" is the same as "n". I don't know if it is a typo or what, but without that assumption, I wouldn't be able to connect the dots. I hope my answer is right.
I don't think I have any particular way to attack the question. I just wrote out the logic. One thing to remember is that function itself has no relation with its output. Often, a function problem will use the input value (in this case x) and try to confuse you into thinking that it has something to do with the output (in this case n). In this problem, if the x and 2^n condition is not given, just remember that x and n has no logical relation with each other. Maybe that will help you see clearer. Hope this helps.
|
|
|
|
|
|
CEO
Joined: 21 Jan 2007
Posts: 2797
Location: New York City
Followers: 5
Kudos [?]:
132
[0], given: 4
|
bkk145 wrote: A.Haung wrote: bkk145,
i only understand what the question was asking after reading your answer. Can you tell me how you attack the question?
Andy Huang My 1000 posts!!! yeah! Actually, I assumed that "N" is the same as "n". I don't know if it is a typo or what, but without that assumption, I wouldn't be able to connect the dots. I hope my answer is right.I don't think I have any particular way to attack the question. I just wrote out the logic. One thing to remember is that function itself has no relation with its output. Often, a function problem will use the input value (in this case x) and try to confuse you into thinking that it has something to do with the output (in this case n). In this problem, if the x and 2^n condition is not given, just remember that x and n has no logical relation with each other. Maybe that will help you see clearer. Hope this helps. N is the same as n. Sorry, should've been more meticulous
OA is A
|
|
|
|
|
|
VP
Joined: 22 Nov 2007
Posts: 1108
Followers: 6
Kudos [?]:
80
[0], given: 0
|
Re: Challenge - Functions [#permalink]
06 Dec 2007, 10:24
f(x) is defined as the largest integer N such that X is divisible by 2^n. Which of the following numbers is the biggest?
f(24)
f(42)
f(62)
f(76)
f(84))
In my opinion A is the answer. A gives us that f(24). Thus, we have f(24)=24/2^n. 24 is 2^3 *3, therefore n could be 3. in B and C n would be 1, while in D n would be 2.
|
|
|
|
|
|
|
Re: Challenge - Functions
[#permalink]
06 Dec 2007, 10:24
|
|
|
|
|
|
|
|
|
|
|
close
