Find all School-related info fast with the new School-Specific MBA Forum
Learn more about the recent changes... close

It is currently 23 May 2013, 03:18
Customize  |  Hide

Search
Register
New posts
Unanswered

Factor p

  Question banks Downloads My Bookmarks Reviews  
  Oldest Best Reply
Search for:
 
Print view
First unread post
Author Message
TAGS:
Manager
Manager
Joined: 29 Apr 2003
Posts: 95
Location: Singapore
Followers: 1

Kudos [?]: 0 [0], given: 0

Factor p [#permalink] New post 08 Feb 2004, 08:44
257.

This is DS problem. Could anyone try it and show the workings?

Does the integer k have a factor p such that 1 < p < k?

1. k> 4!
2. 13! + 2 ≤ K ≤ 13! + 13
SVP
SVP
User avatar
Joined: 30 Oct 2003
Posts: 1963
Location: NewJersey USA
Followers: 3

Kudos [?]: 25 [0], given: 0

GMAT Tests User
 [#permalink] New post 08 Feb 2004, 09:23
A) k > 4! means k > 24 let K be 25 which has factors 1, 5 and 25
1 < 5 < 25
But 29 has factors 1 and 29 and does not satisfy the given condition
So A is insufficient.
B) 13! has all the integer mutiples from 1 and 13
13!+2 is divisible by 2
13!+3 is divisible by 3 and so on
13!+12 is divisible by 12
For all of these 1 < n(from 2 to 12) < 13!+n

B is suffiient.
Senior Manager
Senior Manager
User avatar
Joined: 30 Aug 2003
Posts: 348
Location: dallas , tx
Followers: 1

Kudos [?]: 2 [0], given: 0

GMAT Tests User
 [#permalink] New post 08 Feb 2004, 17:10
anand.. could u pls.. tell me how to crack the sencond sentence.. is any easy or diff way.. what u did is good but a bit confusing..
_________________

shubhangi

SVP
SVP
User avatar
Joined: 30 Oct 2003
Posts: 1963
Location: NewJersey USA
Followers: 3

Kudos [?]: 25 [0], given: 0

GMAT Tests User
 [#permalink] New post 08 Feb 2004, 20:03
I wont be surprised if the answer is D. The stem of the problem is confusing. But I am pretty sure that B is the answer.

1) k>4! involves infinite numbers. This set holds primes and non primes.
Only primes do not satisfy the condition 1<p<k
2) Now 13! = 13*12*11*10*9*8*7*6*5*4*3*2*1 = X
This huge number is divisible by any integer between 1 and 13.
The second condition says that the number K is in between
13!+2 and 13!+13. So what are the possible numbers

13*12*11*10*9*8*7*6*5*4*3*2*1 + 3 divisible by p=3 1<3<(X+3)
13*12*11*10*9*8*7*6*5*4*3*2*1 + 4 divisible by p=4 1<4<(X+4)
----
----
13*12*11*10*9*8*7*6*5*4*3*2*1 + 12 divisible by p=3 1<12<(X+12)

So any number you take it has a factor > 1 and < that number.
Hence B is sufficient

I hope I made it clear.
  [#permalink] 08 Feb 2004, 20:03
    Similar topics Author Replies Last post
Similar
Topics:
 New posts If the prime numbers p and t are the only prime factors of joemama142000 6 18 Dec 2005, 13:32
New posts If the prime numbers p and t are the only prime factors of LM 6 10 Dec 2006, 01:07
New posts (P/S) What is the biggest prime factor? pretttyune 2 26 Nov 2007, 05:43
New posts If the prime numbers p and t are the only prime factors of topmbaseeker 2 10 Feb 2009, 09:03
Popular new posts 2 factor of p snipertrader 16 14 Aug 2009, 04:20
Display posts from previous: Sort by

Factor p

  Question banks Downloads My Bookmarks Reviews  
Print view
First unread post

Moderators: Bunuel, VeritasPrepKarishma

Search for:


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.

Main navigation

GMAT Resources

Partners

MBA Resources

www.gmac.com|www.mba.com