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# Factorial of 8=(2^J)*(3^K)*(5^L)*(7^M). J+K+M+L=

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Factorial of 8=(2^J)*(3^K)*(5^L)*(7^M). J+K+M+L= [#permalink]  05 May 2006, 22:45
Factorial of 8=(2^J)*(3^K)*(5^L)*(7^M). J+K+M+L=?
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Re: Factorial [#permalink]  06 May 2006, 00:37
getzgetzu wrote:
Factorial of 8=(2^J)*(3^K)*(5^L)*(7^M). J+K+M+L=?

8! = 2^7*7*3^2*5 = 7 + 2 + 1 + 1 = 11
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Re: Factorial   [#permalink] 06 May 2006, 00:37
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