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# Family X consists 2 pairs of brothers, Family Y consists of

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Manager
Joined: 06 May 2005
Posts: 61
Location: India
Followers: 1

Kudos [?]: 3 [0], given: 0

Family X consists 2 pairs of brothers, Family Y consists of [#permalink]  10 May 2005, 12:57

Family X consists 2 pairs of brothers, Family Y consists of 3 sisters and Family Z consists of 1 brother / 1 sister. All of them divide themselves into 3 groups to play a game (the group cant be empty). In how many ways can they play
Senior Manager
Joined: 15 Mar 2005
Posts: 419
Location: Phoenix
Followers: 2

Kudos [?]: 12 [0], given: 0

Re: Permutation / Combination [#permalink]  10 May 2005, 15:30
Total number of people = 4 + 3 + 2 = 9.
Therefore number of ways of distributing them in 3 groups, with no group empty = 3^6.
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Director
Joined: 27 Dec 2004
Posts: 908
Followers: 1

Kudos [?]: 19 [0], given: 0

with no group empty, i got 8
Manager
Joined: 06 May 2005
Posts: 61
Location: India
Followers: 1

Kudos [?]: 3 [0], given: 0

Re: Permutation / Combination [#permalink]  11 May 2005, 13:59
kapslock wrote:
Total number of people = 4 + 3 + 2 = 9.
Therefore number of ways of distributing them in 3 groups, with no group empty = 3^6.

What is your reasoning. ( the OA is 9!/ (3!)^4 )
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Its not the fact its your attitude towards the fact

Re: Permutation / Combination   [#permalink] 11 May 2005, 13:59
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