Find all School-related info fast with the new School-Specific MBA Forum

It is currently 22 Jul 2014, 23:50

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Find A and B. (1) (A*B)! is odd (2) A*B is odd

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
SVP
SVP
User avatar
Joined: 03 Feb 2003
Posts: 1614
Followers: 5

Kudos [?]: 38 [0], given: 0

Find A and B. (1) (A*B)! is odd (2) A*B is odd [#permalink] New post 31 Aug 2003, 07:31
Find A and B.

(1) (A*B)! is odd
(2) A*B is odd
SVP
SVP
User avatar
Joined: 03 Feb 2003
Posts: 1614
Followers: 5

Kudos [?]: 38 [0], given: 0

 [#permalink] New post 31 Aug 2003, 10:35
the answer, please!
Intern
Intern
avatar
Joined: 17 Aug 2003
Posts: 40
Location: USA
Followers: 0

Kudos [?]: 1 [0], given: 0

 [#permalink] New post 31 Aug 2003, 18:18
The answer is A.

A=B=1 can be deduced from (A*B)! is odd. but not from A*B is odd
Manager
Manager
User avatar
Joined: 25 Jun 2003
Posts: 96
Followers: 1

Kudos [?]: 0 [0], given: 0

 [#permalink] New post 02 Sep 2003, 05:51
I go with C

From (1) , A = 0 and B = 0
OR A = 1 and B = 0
OR A = 0 and B = 1
OR A = 1 and B = 1 , thus insufficient

From (2) A = 1 and B =1 is one of the many possible solutions

To satisfy both (1) and (2) , A = 1 and B = 1 are the only possible values

_________________

Brainless

Manager
Manager
avatar
Joined: 14 Aug 2003
Posts: 89
Location: barcelona
Followers: 1

Kudos [?]: 0 [0], given: 0

 [#permalink] New post 02 Sep 2003, 07:37
ups, i thought that was a PS, not a DS, sorry :oops:
i go for C as well
Intern
Intern
avatar
Joined: 19 Aug 2003
Posts: 8
Location: Austin, TX
Followers: 0

Kudos [?]: 0 [0], given: 0

 [#permalink] New post 02 Sep 2003, 08:54
Since there is no stipulation on whether A or B are integers, then A=0.25 and B=4 (or vice versa) can satisfy both conditions. The answer would have to be E.
Intern
Intern
avatar
Joined: 17 Aug 2003
Posts: 40
Location: USA
Followers: 0

Kudos [?]: 1 [0], given: 0

 [#permalink] New post 02 Sep 2003, 15:24
Brainless wrote:
I go with C

From (1) , A = 0 and B = 0
OR A = 1 and B = 0
OR A = 0 and B = 1
OR A = 1 and B = 1 , thus insufficient

From (2) A = 1 and B =1 is one of the many possible solutions

To satisfy both (1) and (2) , A = 1 and B = 1 are the only possible values


I think you are right, since 0!=1
SVP
SVP
User avatar
Joined: 03 Feb 2003
Posts: 1614
Followers: 5

Kudos [?]: 38 [0], given: 0

 [#permalink] New post 05 Sep 2003, 09:05
EssQ wrote:
Since there is no stipulation on whether A or B are integers, then A=0.25 and B=4 (or vice versa) can satisfy both conditions. The answer would have to be E.


RIGHT ON THE MONEY!!!
  [#permalink] 05 Sep 2003, 09:05
    Similar topics Author Replies Last post
Similar
Topics:
Experts publish their posts in the topic If a > 0, is 2/(a+b) + 2/(a-b) = 1? ahatoval 4 28 Apr 2013, 19:10
4 Experts publish their posts in the topic If a, b, and c are integer and ab + c is odd, which of the m rdevorse 5 17 Jan 2012, 06:05
4 Experts publish their posts in the topic a is an odd integer and a <>-b Is a^2/|b+a| > a-b ? nades09 7 26 Nov 2010, 19:07
If |a| = b, is a+b < ab 1) a = -b 2) a = -3 artshep 3 09 Dec 2006, 18:13
If AB = 40, what is the value of AB(A + 2B)? (1) A ? B = kpinvictus 10 19 Aug 2004, 23:49
Display posts from previous: Sort by

Find A and B. (1) (A*B)! is odd (2) A*B is odd

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.