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Find A and B. (1) (A*B)! is odd (2) A*B is odd

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SVP
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Find A and B. (1) (A*B)! is odd (2) A*B is odd [#permalink] New post 31 Aug 2003, 08:31
Find A and B.

(1) (A*B)! is odd
(2) A*B is odd
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 [#permalink] New post 31 Aug 2003, 11:35
the answer, please!
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 [#permalink] New post 31 Aug 2003, 19:18
The answer is A.

A=B=1 can be deduced from (A*B)! is odd. but not from A*B is odd
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 [#permalink] New post 02 Sep 2003, 06:51
I go with C

From (1) , A = 0 and B = 0
OR A = 1 and B = 0
OR A = 0 and B = 1
OR A = 1 and B = 1 , thus insufficient

From (2) A = 1 and B =1 is one of the many possible solutions

To satisfy both (1) and (2) , A = 1 and B = 1 are the only possible values
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 [#permalink] New post 02 Sep 2003, 08:37
ups, i thought that was a PS, not a DS, sorry :oops:
i go for C as well
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 [#permalink] New post 02 Sep 2003, 09:54
Since there is no stipulation on whether A or B are integers, then A=0.25 and B=4 (or vice versa) can satisfy both conditions. The answer would have to be E.
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 [#permalink] New post 02 Sep 2003, 16:24
Brainless wrote:
I go with C

From (1) , A = 0 and B = 0
OR A = 1 and B = 0
OR A = 0 and B = 1
OR A = 1 and B = 1 , thus insufficient

From (2) A = 1 and B =1 is one of the many possible solutions

To satisfy both (1) and (2) , A = 1 and B = 1 are the only possible values


I think you are right, since 0!=1
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 [#permalink] New post 05 Sep 2003, 10:05
EssQ wrote:
Since there is no stipulation on whether A or B are integers, then A=0.25 and B=4 (or vice versa) can satisfy both conditions. The answer would have to be E.


RIGHT ON THE MONEY!!!
  [#permalink] 05 Sep 2003, 10:05
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Find A and B. (1) (A*B)! is odd (2) A*B is odd

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