Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 24 May 2013, 18:30

# Find a nonzero integer Q (1) Q is a prime root of Q^Q=Q^3

Author Message
TAGS:
SVP
Joined: 05 Jul 2006
Posts: 1565
Followers: 4

Kudos [?]: 63 [0], given: 35

Find a nonzero integer Q (1) Q is a prime root of Q^Q=Q^3 [#permalink]  12 Oct 2006, 16:48
Find a nonzero integer Q

(1) Q is a prime root of Q^Q=Q^3
(2) Q^2=3^2
Senior Manager
Joined: 31 Jul 2006
Posts: 443
Followers: 3

Kudos [?]: 3 [0], given: 0

Re: Powers again [#permalink]  12 Oct 2006, 17:38
yezz wrote:
Find a nonzero integer Q

(1) Q is a prime root of Q^Q=Q^3
(2) Q^2=3^2

Is it A?

1. Q^Q=Q^3 so Q=3? How does prime root information change things?
2. Q^2 = 3^2. Q = +-3 NOT SUFF.
Senior Manager
Joined: 11 Jul 2006
Posts: 386
Location: TX
Followers: 1

Kudos [?]: 5 [0], given: 0

[#permalink]  12 Oct 2006, 20:05
Based on the question asked , looks like D to me.
Senior Manager
Joined: 28 Aug 2006
Posts: 302
Followers: 7

Kudos [?]: 39 [0], given: 0

Re: Powers again [#permalink]  12 Oct 2006, 23:01
yezz wrote:
Find a nonzero integer Q

(1) Q is a prime root of Q^Q=Q^3
(2) Q^2=3^2

Statement 1: Q^Q=Q^3
so Q could be-1, 1 and 3.But since it is given that Q is prime root of the above equation, it must be 3

So 1 is sufficient

Statement 2: Q^2 = 3^2
i.e Q=3 or Q=-3

So 2 is not sufficient

So A
_________________
Manager
Joined: 01 Feb 2006
Posts: 85
Location: New York
Followers: 1

Kudos [?]: 0 [0], given: 0

[#permalink]  13 Oct 2006, 08:06
It says Q is a non-zero integer, so could be -ve.
Hence, I think it's D. - what say
Senior Manager
Joined: 28 Aug 2006
Posts: 302
Followers: 7

Kudos [?]: 39 [0], given: 0

[#permalink]  13 Oct 2006, 09:16
sujayb wrote:
It says Q is a non-zero integer, so could be -ve.
Hence, I think it's D. - what say

Fine I agree Q is a non-zero integer, and it is because of this From the second statment Q does not have a unique value.

It could be 3 or -3
So statment 2 is not sufficient

HEnce A
_________________
Senior Manager
Joined: 13 Sep 2006
Posts: 286
Location: New York
Followers: 1

Kudos [?]: 0 [0], given: 0

[#permalink]  13 Oct 2006, 10:02
sujayb wrote:
It says Q is a non-zero integer, so could be -ve.
Hence, I think it's D. - what say

I think it is A. Q is supposed to be a Prime root ...I don't think Prime numbers/root can be negative?
_________________

"Never let the fear of striking out get in your wayâ€

Manager
Joined: 08 Jul 2006
Posts: 91
Followers: 1

Kudos [?]: 0 [0], given: 0

Re: Powers again [#permalink]  13 Oct 2006, 11:22
Nsentra wrote:

Is it A?

1. Q^Q=Q^3 so Q=3? How does prime root information change things?
2. Q^2 = 3^2. Q = +-3 NOT SUFF.

I agree with A, what would be an example of a prime root anyway?
Senior Manager
Joined: 28 Aug 2006
Posts: 302
Followers: 7

Kudos [?]: 39 [1] , given: 0

Re: Powers again [#permalink]  13 Oct 2006, 11:30
1
KUDOS
Rayn wrote:
Nsentra wrote:

Is it A?

1. Q^Q=Q^3 so Q=3? How does prime root information change things?
2. Q^2 = 3^2. Q = +-3 NOT SUFF.

I agree with A, what would be an example of a prime root anyway?

Hey rayn, in the first statement we have an equation .
So it is going to have certain number of roots.
One of the roots must be prime...........
_________________
Senior Manager
Joined: 13 Sep 2006
Posts: 286
Location: New York
Followers: 1

Kudos [?]: 0 [0], given: 0

[#permalink]  13 Oct 2006, 11:37
OK - so I dug around to see if prime numbers can be negative and there are two answers to this question: basically in lower level math (high school etc... prime numbers cannot be negative but in highler level complex math they can be. I think GMAT assumes PRIME numbers not to be negative no?
_________________

"Never let the fear of striking out get in your wayâ€

Director
Joined: 06 Sep 2006
Posts: 749
Followers: 1

Kudos [?]: 8 [0], given: 0

[#permalink]  13 Oct 2006, 12:39
Find a nonzero integer Q

(1) Q is a prime root of Q^Q=Q^3
(2) Q^2=3^2

1) Q=3 Sufficient.
2) Q = 3, -3. Can not determine which one. Hence Insufficient.

A.
Director
Joined: 23 Jun 2005
Posts: 853
GMAT 1: 740 Q48 V42
Followers: 3

Kudos [?]: 9 [0], given: 1

[#permalink]  13 Oct 2006, 20:55
There seems to be a question out here:
Can negative numbers be considered prime numbers in GMAT?
Manager
Joined: 01 Oct 2006
Posts: 246
Followers: 1

Kudos [?]: 4 [0], given: 0

[#permalink]  14 Oct 2006, 13:22
anandsebastin wrote:
There seems to be a question out here:
Can negative numbers be considered prime numbers in GMAT?

Manhattan GMAT defines prime numbers as: Prime number is an integer (greater than 1) with exactly 2 factors : 1 and itself.

I would think that negative numbers should not be considered as prime. They are referred to as the associates of the positive prime numbers.
Manager
Joined: 08 Jul 2006
Posts: 91
Followers: 1

Kudos [?]: 0 [0], given: 0

[#permalink]  14 Oct 2006, 13:51
What is the value of the prime number?

1) 13<x<19
2) x^2/17 = 17

After I give you the OA, we'll decide whether negative primes are welcomed on the GMAT.
SVP
Joined: 01 May 2006
Posts: 1837
Followers: 8

Kudos [?]: 71 [0], given: 0

[#permalink]  14 Oct 2006, 13:59
Rayn wrote:
What is the value of the prime number?

1) 13<x<19
2) x^2/17 = 17

After I give you the OA, we'll decide whether negative primes are welcomed on the GMAT.

(D) for me. A prime number is always positive and superior to 1
Senior Manager
Joined: 30 Aug 2006
Posts: 375
Followers: 2

Kudos [?]: 4 [0], given: 0

[#permalink]  14 Oct 2006, 14:52
I'd say D too (but i'm guessing its not right )
SVP
Joined: 01 May 2006
Posts: 1837
Followers: 8

Kudos [?]: 71 [0], given: 0

[#permalink]  14 Oct 2006, 15:02
londonluddite wrote:
I'd say D too (but i'm guessing its not right )

It has to be right

OG 11, page 108, paragraph 5 : A prime number is a positive integer that has exactly 2 different positive divisors, 1 and itself
Manager
Joined: 08 Jul 2006
Posts: 91
Followers: 1

Kudos [?]: 0 [0], given: 0

[#permalink]  14 Oct 2006, 15:07
OA is A.

We must consider -17 as a possible prime. (But I guess they are mistaken, since OG clearly wants us to consider solely +'ve integers)

Source: McGrawHill Test Prep.
SVP
Joined: 01 May 2006
Posts: 1837
Followers: 8

Kudos [?]: 71 [0], given: 0

[#permalink]  14 Oct 2006, 15:14
Rayn wrote:
OA is A.

We must consider -17 as a possible prime. (But I guess they are mistaken, since OG clearly wants us to consider solely +'ve integers)

Source: McGrawHill Test Prep.

Yes... The most important is the OG view so the GMAT rules to know and apply
Manager
Joined: 08 Jul 2006
Posts: 91
Followers: 1

Kudos [?]: 0 [0], given: 0

[#permalink]  14 Oct 2006, 15:27
Could someone who understands differential speeds look at my last post under Beginners Forum (Re-worked questions), Page 5 and explain the guys reasoning to me?

http://www.gmatclub.com/phpbb/viewtopic ... 0&start=80
[#permalink] 14 Oct 2006, 15:27
Similar topics Replies Last post
Similar
Topics:
P, Q, and R are nonzero integers. Is P/(Q*R) an integer? (1) 5 29 May 2003, 03:30
Find a nonzero integer Q (1) Q is a prime root of Q^Q=Q^3 9 10 Jun 2003, 00:07
Find a nonzero integer Q (1) Q is a prime root of Q^Q=Q^3 12 11 Mar 2005, 17:11
Is \frac{4Q}{11} a positive integer? 1. Q is a prime number 5 09 Sep 2008, 18:53
5 If n=(p/q) (p and q are nonzero integers), is an integer? 1. 8 21 Sep 2010, 21:43
Display posts from previous: Sort by