Find an integer M. (1) M^M=M^3 (2) =1 : Quant Question Archive [LOCKED]
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# Find an integer M. (1) M^M=M^3 (2) =1

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Find an integer M. (1) M^M=M^3 (2) =1 [#permalink]

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21 May 2003, 23:54
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Find an integer M.

(1) M^M=M^3
(2) [M^3]=1

Manager
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22 May 2003, 00:02
again a classic.......would go with E

either u had the best sex of your life or u just met God.....

those are the only two reasons i can think of for these problems that you created
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22 May 2003, 00:16
You are right; it is E.
I have neither met God, nor have I had great sex.
This is because I have just been granted admin rights!
Manager
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22 May 2003, 00:21
SVP
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22 May 2003, 00:27
To some degree of course. I can add new smiles and erase old ones. A cool job, isn't it?
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22 May 2003, 00:31
thanks for the smiles.........they are
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22 May 2003, 00:36
There is a great Russian site: http://smiles.elze.ru/index_eng.htm
The best collection of smiles in the net.
Intern
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22 May 2003, 10:50
Can someone explain why it's E?
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22 May 2003, 17:37
from statement 1

(-1)^-1 = -1 & (-1)^3 = -1
&
(1)^1 = 1 & (1)^3 =1

therefore M = 1 or -1

from statment 2

[(-1)^3] = 1
&
[(1)^3] = 1

therefore M = 1 or -1

from both statements together we cannot say whether M =1 or -1

hope that helps
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22 May 2003, 20:04
brstorewala wrote:
from statment 2
[(-1)^3] = 1

But [(-1)^3] = -1, does it not???

That simply leaves [(1)^3] = 1...so isn't statement 2 sufficient?
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22 May 2003, 20:09
[...] is modulus sign......the sign is always positive
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22 May 2003, 21:02
brstorewala wrote:
from statement 1

(-1)^-1 = -1 & (-1)^3 = -1
&
(1)^1 = 1 & (1)^3 =1

therefore M = 1 or -1

from statment 2

[(-1)^3] = 1
&
[(1)^3] = 1

therefore M = 1 or -1

from both statements together we cannot say whether M =1 or -1

hope that helps

The trick is that (1) has THREE solutions! 1, -1, and 3
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22 May 2003, 21:23
stolyar wrote:
brstorewala wrote:
from statement 1

(-1)^-1 = -1 & (-1)^3 = -1
&
(1)^1 = 1 & (1)^3 =1

therefore M = 1 or -1

from statment 2

[(-1)^3] = 1
&
[(1)^3] = 1

therefore M = 1 or -1

from both statements together we cannot say whether M =1 or -1

hope that helps

The trick is that (1) has THREE solutions! 1, -1, and 3

ohhhhhhh yessss.....luckily i got the answer correct.........
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22 May 2003, 21:53
It is the first time I have caught you. Even so, you have managed to safely escape.
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25 May 2003, 23:39
what is 0^0..is this another possible solution from 1?
Founder
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25 May 2003, 23:53
skoper wrote:
what is 0^0..is this another possible solution from 1?

I think we 've decided that 0^0 is undefined; I will ask the people in charge about it, but so far, the unanimous decision has been UNDEFINED

-=-
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25 May 2003, 23:56
bb wrote:
skoper wrote:
what is 0^0..is this another possible solution from 1?

I think we 've decided that 0^0 is undefined; I will ask the people in charge about it, but so far, the unanimous decision has been UNDEFINED

-=-

i punched this into my windows calculator right now

Founder
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26 May 2003, 00:01
skoper wrote:
bb wrote:
skoper wrote:
what is 0^0..is this another possible solution from 1?

I think we 've decided that 0^0 is undefined; I will ask the people in charge about it, but so far, the unanimous decision has been UNDEFINED

-=-

i punched this into my windows calculator right now

The funny thing is that you are right

and nobody did it!

I think you just deserved a premium membership just for that.

I can't stop laughing.

-=-=
Founder
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Kudos [?]: 22940 [0], given: 4510

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26 May 2003, 00:02
Or maybe it is Evil Microsoft?
Founder
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26 May 2003, 00:03
it is indeed evil Microsoft - my Sharp Scientific Calculator gave Error code 2, whatever that means.
26 May 2003, 00:03

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