Find the gcd of a, b, and c (1) gcd(a, b) = 3 (2) gcd(b, c) : DS Archive
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# Find the gcd of a, b, and c (1) gcd(a, b) = 3 (2) gcd(b, c)

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Find the gcd of a, b, and c (1) gcd(a, b) = 3 (2) gcd(b, c) [#permalink]

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13 Apr 2004, 18:08
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Find the gcd of a, b, and c

(1) gcd(a, b) = 3
(2) gcd(b, c) = 4
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14 Apr 2004, 22:37
Clearly, either set taken alone is not sufficient.
Consider them combined:
b is divisible by both 3 and 4, so b=12n
a is divisible by 3, but not even
c seems to be 4

GCD[a, b, c]=1

C.
14 Apr 2004, 22:37
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# Find the gcd of a, b, and c (1) gcd(a, b) = 3 (2) gcd(b, c)

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