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# Find the probability that a leap year selected at random

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Joined: 25 Jan 2013
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Find the probability that a leap year selected at random [#permalink]

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30 Jan 2013, 22:30
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Find the probability that a leap year selected at random will have 53 Sundays

A. 6/7
B. 5/7
C. 4/7
D. 3/7
E. 2/7
[Reveal] Spoiler: OA

Last edited by Bunuel on 31 Jan 2013, 03:49, edited 2 times in total.
Renamed the topic and edited the question.
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Re: Find the probability that a leap year selected at random [#permalink]

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31 Jan 2013, 03:48
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antoxavier wrote:
Find the probability that a leap year selected at random will have 53 Sundays

A. 6/7
B. 5/7
C. 4/7
D. 3/7
E. 2/7

There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays and 2 days.

These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat, Sun} and {Sun, Mon} (7 cases). In order to have 53 Sundays we should have either {Sat, Sun} or {Sun, Mon} case.

The probability of that is 2/7.

Answer: E.

Hope it's clear.

P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to the rule #3 (the name of a topic MUST be the first 40 characters (~the first two sentences) of the question).
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Re: Find the probability that a leap year selected at random [#permalink]

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25 Jul 2014, 20:19
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Re: Find the probability that a leap year selected at random [#permalink]

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20 Jun 2016, 18:52
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Find the probability that a leap year selected at random   [#permalink] 20 Jun 2016, 18:52
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# Find the probability that a leap year selected at random

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