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Find the probability that a leap year selected at random

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Joined: 25 Jan 2013
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Kudos [?]: 1 [0], given: 11

Find the probability that a leap year selected at random [#permalink] New post 30 Jan 2013, 22:30
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Difficulty:

  35% (medium)

Question Stats:

64% (01:30) correct 35% (00:47) wrong based on 74 sessions
Find the probability that a leap year selected at random will have 53 Sundays

A. 6/7
B. 5/7
C. 4/7
D. 3/7
E. 2/7
[Reveal] Spoiler: OA

Last edited by Bunuel on 31 Jan 2013, 03:49, edited 2 times in total.
Renamed the topic and edited the question.
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Re: Find the probability that a leap year selected at random [#permalink] New post 31 Jan 2013, 03:48
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antoxavier wrote:
Find the probability that a leap year selected at random will have 53 Sundays

A. 6/7
B. 5/7
C. 4/7
D. 3/7
E. 2/7


There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays and 2 days.

These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat, Sun} and {Sun, Mon} (7 cases). In order to have 53 Sundays we should have either {Sat, Sun} or {Sun, Mon} case.

The probability of that is 2/7.

Answer: E.

Hope it's clear.

P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to the rule #3 (the name of a topic MUST be the first 40 characters (~the first two sentences) of the question).
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Re: Find the probability that a leap year selected at random   [#permalink] 31 Jan 2013, 03:48
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