antoxavier wrote:
Find the probability that a leap year selected at random will have 53 Sundays
A. 6/7
B. 5/7
C. 4/7
D. 3/7
E. 2/7
There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays and 2 days.
These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat,
Sun} and {
Sun, Mon} (7 cases). In order to have 53 Sundays we should have either {Sat,
Sun} or {
Sun, Mon} case.
The probability of that is 2/7.
Answer: E.
Hope it's clear.
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60% (01:54) correct
