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I remember now that I had 1/8 as the answer in my mind when i framed the question.........it only mentions about the first three heads......so essentially the last two throws are useless.....

the answer will always be 1/8 irrespective of the number of throws.......i wonder why i did not reply to stolyar's posting........or maybe i did thru a PM.

Say, if instead of 5 coins we had 1,241,352 coins. What is the p that first 3 coins will have heads? It is still 1/8, but i doubt you can calculate 2^1,241,352!

Best is to use 1/2^3. Three independent events.

I guess this is what brstorewala means when saying the answer is

hey....I got 1/8 too!!! [#permalink]
06 Jun 2003, 12:00

Well,Here is how I woked it out.....
P(getting a head)=1/2 so P(getting a head first three times)=1/2*1/2*1/2=1/8!!!!!!!Ofcourse.the p(of getting a tail )= 1/2 too.I am not sure about this logic!!!! _________________

Its not about you getting knocked down,Its about how fast you get back up again!!!!

Given the recent news this is way overdue, but see below my first interview report for INSEAD. I met with a senior politician alum who, understandably, had a busy schedule. The...

One thing I did not know when recruiting for the MBA summer internship was the following: just how important prior experience in the function that you're recruiting for...