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Five kilograms of oranges contained 98% of water. [#permalink]

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27 Oct 2012, 06:30

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Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?

(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2

I've got the answer (A) but the correct one is (C). How can it be possible? Please, share your ideas!

Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?

(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2

If C is the answer, then the question means that the concentration of water the newt day became 96%.

Out of 5 kilograms 98%, or 4.9 kilograms was water and 0.1 kilograms was non-water.

The next day, after some water evaporated, oranges became 96% water and 4% of non-water, so the next day 0.1 kilograms of non-water composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.1 --> x=2.5 kilograms.

Re: Five kilograms of oranges contained 98% of water. [#permalink]

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29 Oct 2012, 06:33

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Bunuel wrote:

Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?

(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2

If C is the answer, then the question means that the concentration of water the newt day became 96%.

Out of 5 kilograms 98%, or 4.9 kilograms was water and 0.1 kilograms was non-water.

The next day, after some water evaporated, oranges became 96% water and 4% of non-water, so the next day 0.1 kilograms of non-water composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.1 --> x=2.5 kilograms.

Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?

(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2

If C is the answer, then the question means that the concentration of water the newt day became 96%.

Out of 5 kilograms 98%, or 4.9 kilograms was water and 0.1 kilograms was non-water.

The next day, after some water evaporated, oranges became 96% water and 4% of non-water, so the next day 0.1 kilograms of non-water composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.1 --> x=2.5 kilograms.

I also thought that it is A, Bunuel do you think that it is real GMAT like question, because i think that it is a little unclear.

I agree, the wording is ambiguous. So, not a GMAT like question. Check the link in my previous post for similar question with better wording.
_________________

Re: Five kilograms of oranges contained 98% of water. [#permalink]

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19 Jun 2013, 19:02

rainbooow wrote:

Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?

(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2

I've got the answer (A) but the correct one is (C). How can it be possible? Please, share your ideas!

Re: Five kilograms of oranges contained 98% of water. [#permalink]

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05 Oct 2015, 13:12

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Five kilograms of oranges contained 98% of water. [#permalink]

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27 Jun 2016, 23:27

Bunuel wrote:

Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?

(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2

If C is the answer, then the question means that the concentration of water the newt day became 96%.

Out of 5 kilograms 98%, or 4.9 kilograms was water and 0.1 kilograms was non-water.

The next day, after some water evaporated, oranges became 96% water and 4% of non-water, so the next day 0.1 kilograms of non-water composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.1 --> x=2.5 kilograms.

I hope the GMAT differentiates clearly between "percentage" and "percentage points"...If it doesn't..then please tell how would it be stated differently..so there are no surprises in the test.
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gmatclubot

Five kilograms of oranges contained 98% of water.
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27 Jun 2016, 23:27

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