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Five people are running in a race. The first one to finish [#permalink]
13 Mar 2012, 19:15

1

This post received KUDOS

2

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

15% (low)

Question Stats:

70% (01:32) correct
30% (00:36) wrong based on 142 sessions

Five people are running in a race. The first one to finish wins a gold medal, the second wins a silver medal and the third wins a bronze medal. How many different arrangements of medal winners, in order from first to third, are possible?

Re: permutations & Combinations [#permalink]
13 Mar 2012, 20:14

2

This post received KUDOS

same type of question where order doesn't matter

Five people are running in a race. The first three to finish win gift certificates. How many different groups of people could win the gift certificates? _________________

Press +1 Kudos rather than saying thanks which is more helpful infact..

Re: Five people are running in a race. The first one to finish [#permalink]
23 Mar 2012, 01:08

2

This post received KUDOS

Expert's post

1

This post was BOOKMARKED

pappueshwar wrote:

hey all, whats the answer?

i got it as 60 . is that wrong ?

OA is given under the spoiler in the initial post.

Five people are running in a race. The first one to finish wins a gold medal, the second wins a silver medal and the third wins a bronze medal. How many different arrangements of medal winners, in order from first to third, are possible? A. 5 B. 10 C. 60 D. 120 E. 125

\(C^3_5*3!=60\), where \(C^3_5\) is ways to select the group of 3 winners out of 5 contestants and 3! is ways to arranging them (alternately you can just do \(P^3_5=60\)).

Re: Five people are running in a race. The first one to finish [#permalink]
18 Oct 2013, 00:15

Bunuel wrote:

pappueshwar wrote:

hey all, whats the answer?

i got it as 60 . is that wrong ?

OA is given under the spoiler in the initial post.

Five people are running in a race. The first one to finish wins a gold medal, the second wins a silver medal and the third wins a bronze medal. How many different arrangements of medal winners, in order from first to third, are possible? A. 5 B. 10 C. 60 D. 120 E. 125

\(C^3_5*3!=60\), where \(C^3_5\) is ways to select the group of 3 winners out of 5 contestants and 3! is ways to arranging them (alternately you can just do \(P^3_5=60\)).

Answer: C.

Hope it helps.

Hello Bunuel,

I didn't understand why you used \(P^3_5=60\) to solve this question. Also, the actual evaluation of it seems to get me - I know this is a silly point but I still get it wrong -

I evaluate as follows:

\(P^3_5\)= 5!/3! = 5*4*3*2*1/ 3*2*1 = 20. where am I going wrong? _________________

Re: Five people are running in a race. The first one to finish [#permalink]
18 Oct 2013, 04:37

Expert's post

SaraLotfy wrote:

Bunuel wrote:

pappueshwar wrote:

hey all, whats the answer?

i got it as 60 . is that wrong ?

OA is given under the spoiler in the initial post.

Five people are running in a race. The first one to finish wins a gold medal, the second wins a silver medal and the third wins a bronze medal. How many different arrangements of medal winners, in order from first to third, are possible? A. 5 B. 10 C. 60 D. 120 E. 125

\(C^3_5*3!=60\), where \(C^3_5\) is ways to select the group of 3 winners out of 5 contestants and 3! is ways to arranging them (alternately you can just do \(P^3_5=60\)).

Answer: C.

Hope it helps.

Hello Bunuel,

I didn't understand why you used \(P^3_5=60\) to solve this question. Also, the actual evaluation of it seems to get me - I know this is a silly point but I still get it wrong -

I evaluate as follows:

\(P^3_5\)= 5!/3! = 5*4*3*2*1/ 3*2*1 = 20. where am I going wrong?

First of all \(P^n_k=\frac{n!}{(n-k)!}\), thus \(P^3_5=5!/(5-3)!=60\).

Next, consider the runners to be A, B, C, D and E.

\(P^3_5\) gives all different ordered triplets from 5: ABC ACB BAC BCA CAB CBA

Re: Five people are running in a race. The first one to finish [#permalink]
30 Oct 2014, 08:20

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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Back to hometown after a short trip to New Delhi for my visa appointment. Whoever tells you that the toughest part gets over once you get an admit is...